Chapter 23: Q40P (page 631)
Explain how slinization reduces tailing of chromatographic peaks.
Short Answer
Silanization creates hydroxyl groups that can form strong hydrogen bonds.
Chapter 23: Q40P (page 631)
Explain how slinization reduces tailing of chromatographic peaks.
Silanization creates hydroxyl groups that can form strong hydrogen bonds.
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(a) Why is it difficult to extract the complex of aluminum into an organic solvent but easy to extract the complex?
(b) If you need to bring the complex into the organic solvent, should you add a phase transfer agent with a hydrophobic cation or a hydrophobic anion?
Consider the extraction of from aqueous solution into organic solution by reaction with protonated ligand HL : .Rewrite Equation 23 - 13 in terms of role="math" localid="1654863844402" and express in terms of the constants in Equation 23 - 13 . Give a physical reason why each constant increases or decreases
The weak base equilibrates between water (phase 1) and benzene (phase 2)
(a) Define the distribution coefficient, D for this system.
(b) Explain the difference between D and K the partition coefficient.
(c) Calculate D at
(d) Will D be greater or less at ? Explain why.
Isotopic compounds (isotopologues) are separated in Figure 23-15 by repeated passage through a pair of columns. Each cycle in the figure represents
one pass through length L = 25 cm containing
L theoretical plates. The relative retention () is and the retention factor for
L-phenylalanine is . (a) The observed resolution after 10 cycles is 1.60 .
Calculate the number of theoretical plates, N , in column length L . The mixture
has passed through length 10L in 10 cycles.
(b) Find the plate height in .
(c) Predict the resolution expected from two cycles. The observed value is 0.71 .
The theoretical limit for extracting solute Sfrom into phase2 is attained by dividing into an infinite number of infinitesimally small portions and conducting an infinite number of extractions. With a partition coefficient, the limiting fraction of solute remaining in phase . Let volume be divided intoequal portions to conduct extractions. Find the fraction of S extracted into phase 2 for n = 1,2, and 10extractions. How many portions are required to attain 95%of the theoretical limit?
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