(a) Why is it difficult to extract the complex of aluminum into an organic solvent but easy to extract the complex?

(b) If you need to bring the EDTAcomplex into the organic solvent, should you add a phase transfer agent with a hydrophobic cation or a hydrophobic anion?

Short Answer

Expert verified

A hydrophobic cation is needed to bring the hydrophobic complex to the organic solvent.

Step by step solution

01

of 2 

(a)

  • Here, it is to be noted that that EDTA complex with aluminium is in the anionic form AI[EDTA]-
  • Here, 8-hydroxyquinolinecomplex with aluminium is neutralAI8-hydroxyquinoline3.

neutral species are more soluble in an organic solvent, and the charged species are more soluble in aqueous

02

of 2

(b)

  • As, EDTA complex is in anionic form, we would need a hydrophobic cation to bring the hydrophobic complex to the organic solvent.

Result:

A hydrophobic cation is needed to bring the hydrophobic complex to the organic solvent as EDTA complex is in anionic form.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An open tubular column has an inner diameter of 207μmand the thickness of the stationary phase on the inner wall is 0.50μm. Unretained solute passes through in 63s and a particular solute emerges in 433s . Find the partition coefficient for this solute and find the fraction of time spent in the stationary phase.

23-32. Chromatograms of compounds A and B were obtained at the same flow rate with two columns of equal length. The value of tmis 1.3m in both cases.


(a) Which column has more theoretical plates?

(b) Which column has a larger plate height?

(c) Which column gives higher resolution?

(d) Which column gives a greater relative retention?

(e) Which compound has a higher retention factor?

(f) Which compound has a greater partition coefficient?

(g) What is the numerical value of the retention factor of peak A?

(h) What is the numerical value of the retention factor of peak B?

(i) What is the numerical value of the relative retention?

The theoretical limit for extracting solute Sfrom Phase1(volumeV1)into phase2 (volumeV2)is attained by dividing V2into an infinite number of infinitesimally small portions and conducting an infinite number of extractions. With a partition coefficient, K=[S]2/[S]1the limiting fraction of solute remaining in phase 1is2qlimit=e-(V2/V1)K(V1=V2=50mLandK=2). Let volume V2be divided intoequal portions to conduct extractions. Find the fraction of S extracted into phase 2 for n = 1,2, and 10extractions. How many portions are required to attain 95%of the theoretical limit?

Solute S has a partition coefficient of 4.0 between water (phase 1) and chloroform (phase 2) in Equation 23-1.

(a) Calculate the concentration of in chloroform if[S]aqis 0.020M.

(b) If the volume of water is 80.0 mL and the volume of chloroform is 10.0 mL, find the quotient localid="1654852656619" (molSinchloroform)(molSinwater).

The retention volume of a solute is 76.2mL for a column withVm=16.6mL andVs=12.7mL . Calculate the retention factor and the partition coefficient for this solute.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free