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Chapter 7: Q6P (page 158)
Why are ultrapure acid solvents required to dissolve samples
for trace analysis?
Ultrapure acid solvents are utilised to dissolve samples since this analysis demands a low number of contaminants in the substance.
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What is the difference between a reagent-grade chemical and a primary standard?
A sample of is titrated with role="math" localid="1654840699323" The solubility product of is. At each of the following volumes of titrant, calculate role="math" localid="1654840898095" and construct a graph of versus milliliters of added:
Derive an expression analogous to Equation 7-12 for the titration of (concentration, ,volume=) with (titrant concentration=). Your equation should allow you to compute the volume of titrant as a function of.
A procedure for determining halogens in organic compounds
uses an argentometric titration. To 50 mL of anhydrous ether is added
a carefully weighed sample (10–100 mg) of unknown, plus 2 mL of
sodium dispersion and 1 mL of methanol. (Sodium dispersion is finely
divided solid sodium suspended in oil. With methanol, it makes
sodium methoxide,, which attacks the organic compound,
liberating halides.) Excess sodium is destroyed by slow addition of
2-propanol, after which 100 mL of water are added. (Sodium should
not be treated directly with water, because the produced can
explode in the presence of This
procedure gives a two-phase mixture, with an ether layer floating on
top of the aqueous layer that contains the halide salts. The aqueous
layer is adjusted to pH 4 and titrated with , using the electrodes in
Figure 7-5. How much 0.025 70 M solution will be required to
reach each equivalence point when 82.67 mg of 1-bromo-4-chlorobutaneare analysed ?
Arsenic(III) oxide is available in pure form and is a useful (but carcinogenic) primary standard for oxidizing agents such as .The is dissolved in base and then titrated with in acidic solution. A small amount of iodideor iodate is used to catalyze the reaction between and.
(c) It was found that 0.1468 g of required 29.98 mL of solution for the faint color of unreacted to appear. In a blank titration, 0.03 mL of was required to produce enough color to be seen. Calculate the molarity of the permanganate solution.
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