Chapter 22: QAE (page 598)

Measure the width at half-height of the peak at m/z53and calculate the resolving power of the spectrometer from the expression $m / m_{1 / 2}$ . Would you expect to be able to resolve two peaks at 100and 101Da?

Short Answer

Expert verified

The width which is present at half-height is 0.60 m/z .

Step by step solution

Definition of molecule.

Resolving power:

- The resolving power of a mass spectrometer is used to distinguish two peaks of comparable mass.

- The formula for resolving power is as follows: Where the value of mis less than the value of m/z.

Step 2: The resolving power of the spectrometer from the expression m/m1/2 .

The width which is present at half-height is 0.60m/z .

The provided peak is located at m/z - 53

Now, using the above-mentioned formula, compute the resolving power.

Resolving power $= \frac{53}{0.60} = 88$

Resolving power = 88

Now barely distinguish 2 peaks differing by 1 Da at a mass of 88 Da but not able to distinguish 2 peaks at 100 Da and 101 Da.

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Measure the width at half-height of the peak at m/z53and calculate the resolving power of the spectrometer from the expression $m / m_{1 / 2}$ . Would you expect to be able to resolve two peaks at 100and 101Da?

Short Answer

Step by step solution

Definition of molecule.

Step 2: The resolving power of the spectrometer from the expression m/m1/2 .

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Measure the width at half-height of the peak at m/z53and calculate the resolving power of the spectrometer from the expression m/m1/2. Would you expect to be able to resolve two peaks at 100and 101Da?

Short Answer

Step by step solution

Definition of molecule.

Step 2: The resolving power of the spectrometer from the expression m/m1/2 .

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Ionic and Molecular Compounds

Chemical Analysis

Physical Chemistry

Chemical Reactions

Kinetics

Study anywhere. Anytime. Across all devices.

Measure the width at half-height of the peak at m/z53and calculate the resolving power of the spectrometer from the expression $m / m_{1 / 2}$ . Would you expect to be able to resolve two peaks at 100and 101Da?