Chapter 9: Q1IQ (page 190)

What concentrations of H⁺ and OH^- are produced by H₂O dissociation in 0.01 M NaOH?

Short Answer

Expert verified

The concentrations of H⁺ and OH^- are produced by H₂O dissociation in 0.01 M NaOH are 10^-12M and 0.01 M respectively.

Step by step solution

Introduction

NaOH is a strong base which is highly soluble in water. Dissociation of NaOH in water gives the following reaction

$N a O H \overset{H_{2} O}{\to} N a^{+} + O H^{-}$

Here it is asked to findconcentrations of H⁺ and OH^- are produced by H₂O dissociation in 0.01 M NaOH.

Determine the concentration

As NaOH is a strong base therefore it can be said that the concentration of OH^- in the solution will be 0.01 M.

Now the concentration of H⁺ will be

$\begin{array}{rcl} [H^{+}] [O H^{-}] & = & K_{w} \\ K_{w} & = & 10^{- 14} \\ [H^{+}] [O H^{-}] & = & 10^{- 14} \\ [H^{+}] [0.01] & = & 10^{- 14} \\ [H^{+}] & = & \frac{10^{- 14}}{0.01} \\ [H^{+}] & = & 10^{- 12} M \end{array}$

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What concentrations of H⁺ and OH^- are produced by H₂O dissociation in 0.01 M NaOH?

Short Answer

Step by step solution

Introduction

Determine the concentration

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What concentrations of H+ and OH- are produced by H2O dissociation in 0.01 M NaOH?

Short Answer

Step by step solution

Introduction

Determine the concentration

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What concentrations of H⁺ and OH^- are produced by H₂O dissociation in 0.01 M NaOH?