Find the pH and concentrations of(CH3)3Nand(CH3)3NH+ in a 0.060M solution of trimethylamine.

Short Answer

Expert verified

Concentration of(CH3)3Nis 0.058M, Concentration of(CH3)3NH+is 1.91×10-3 M and the pH is 11.28

Step by step solution

01

Introduction

We need to write the chemical equation that describes the ionization of trimethylamine

CH33N+H2OCH33NH++OH-CH33N=0.06-xCH33NH+=OH-=x

02

Calculate the value of Kb

We have to calculate value ofKbfrom the value ofKwandKabecause the product isOH-

Kb=Kw/Ka=6.3×10-5

03

Find out the value of x

Now calculate the value of x by using value ofKb

Kb=x20.06-x6.3×10-5=x20.06-xx=1.91×10-3

04

Calculate the pH of solution

Since our product isso first we will have to calculatepOHand thenpH

pOH=-logx=-log1.91×10-3=2.72pH=14-pOH=14-2.72=11.28

05

Calculate the concentration of (CH3)3N

CH33N=0.06-xCH33N=0.06-1.91×10-3CH33N=0.058M

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free