Write the chemical reaction whose equilibrium constant is

(a) ${\mathbf{K}}_{\mathbf{a}}$ for benzoic acid, ${\mathbf{C}}_{\mathbf{6}}{\mathbf{H}}_{\mathbf{5}}{\mathbf{CO}}_{\mathbf{2}}\mathbf{H}$

(b) ${\mathbf{K}}_{\mathbf{b}}$ for benzoate ion,${\mathbf{C}}_{\mathbf{6}}{\mathbf{H}}_{\mathbf{5}}{\mathbf{CO}}_{\mathbf{2}}^{\mathbf{2}\mathbf{-}}$

(c) ${\mathbf{K}}_{\mathbf{b}}$ for aniline, ${\mathbf{C}}_{\mathbf{6}}{\mathbf{H}}_{\mathbf{5}}{\mathbf{NH}}_{\mathbf{2}}$

(d) ${\mathbf{K}}_{\mathbf{a}}$ for anilinium ion, ${\mathbf{C}}_{\mathbf{6}}{\mathbf{H}}_{\mathbf{5}}{\mathbf{NH}}_{\mathbf{3}}^{\mathbf{+}}$

A chemical reaction is a process in which reactants are converted into products.

Protonation is the addition of a proton to an atom, ion, or molecule.

In the expression of the acid dissociation constant, ${\mathbf{H}}^{\mathbf{+}}$will be released.

In the expression of base dissociation constant, data-custom-editor="chemistry" ${\mathbf{OH}}^{\mathbf{-}}$will be released.

The acid dissociation constant expression for benzoic acid is as shown below:

${\mathrm{C}}_6{\mathrm{H}}_5\mathrm{COOH}\rightleftharpoons {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{COO}}^{-}+{\mathrm{H}}^{+}$

It shows the release of a proton.

The base dissociation constant expression for benzoic acid is as shown below:

It shows the release of a hydroxide ion.

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{COO}}^{-}+{\mathrm{H}}_2\mathrm{O}\rightleftharpoons {\mathrm{C}}_6{\mathrm{H}}_5\mathrm{COOH}+{\mathrm{OH}}^{-}$

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2+{\mathrm{H}}_2\mathrm{O}\rightleftharpoons {\mathrm{C}}_6{\mathrm{H}}_5\mathrm{N}〖{\mathrm{H}}_3{〗}^{+}+{\mathrm{OH}}^{-}$

The acid dissociation constant expression for anilinium ion is as shown below:

${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_3^{+}\rightleftharpoons {\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NH}}_2+{\mathrm{H}}^{+}$

It shows the release of a proton.