Chapter 9: QAE (page 207)

Using activity coefficients correctly, find the pH of $1.0 \times 10^{- 2} MNaOH$ .

Short Answer

Expert verified

The pH of $1.0 \times 10^{- 2} MNaOH is 11.95$ .

Step by step solution

Concept used.

The relationship between pH and pOH is given as,

$pH + pOH = - {logK}_{w} pH + pOH = 14 A_{I^{+}} A_{OH} = K_{w} A_{H^{+}} = \frac{K_{w}}{A_{H^{-}}} pH = a - {logA}_{H^{+}} pH = - \log {[H^{+}]}_{+}$

Step2: Calculate the pH of 1.0×10-2 MNaOH.

Molarity of $NaOH = 1.0 \times 10^{- 2} M$

$[{OH}^{-}] = 1.0 \times 10^{- 2} M γ_{OH} = 0.900 μ = 0.0100 M$

Now calculate pH,

$A_{H^{+}} = \frac{K_{v}}{{IOHY}_{{OH}^{-}}} A_{H^{+}} = \frac{1.0 \times 10^{- 14}}{(1.0 \times 10^{2}) (0.900)} A_{H^{+}} = 1.11 \times 10^{- 12} pH = - \log [A_{1 +}] pH = 11.95$

The pH of $1.0 \times 10^{- 2} MNaOH = 11.95$ .

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Using activity coefficients correctly, find the pH of $1.0 \times 10^{- 2} MNaOH$ .

Short Answer

Step by step solution

Concept used.

Step2: Calculate the pH of 1.0×10-2 MNaOH.

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Using activity coefficients correctly, find the pH of1.0×10-2MNaOH.

Short Answer

Step by step solution

Concept used.

Step2: Calculate the pH of 1.0×10-2 MNaOH.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Ionic and Molecular Compounds

Inorganic Chemistry

Organic Chemistry

Chemistry Branches

Making Measurements

Study anywhere. Anytime. Across all devices.

Using activity coefficients correctly, find the pH of $1.0 \times 10^{- 2} MNaOH$ .