Chapter 10: Q1P (page 230)

Consider ${HA}^{-}$ , the intermediate form of a diprotic acid. $K_{2}$ for this species is $10^{- 4}$ and $K_{b}$ is $10^{- 8}$ . Nonetheless, the $K_{a}$ and $K_{b}$ reactions proceed to nearly the same extent when NaHA is dissolved in water. Explain.

Short Answer

Expert verified

The $K_{b}$ reaction continues to the same extent as the $K_{a}$ reaction.

Step by step solution

Definition of diprotic acid.

Any acid containing two hydrogen atoms in its molecule that can be released or ionised in water is called diprotic acid.

Explanation.

Thereaction is written as:

${HA}^{-} \to H^{+} + A^{2 -}$

Thereaction is written as:

${HA}^{-} + H_{2} O \to H_{2} A + {OH}^{-}$

The $K_{a}$ reaction produces $H^{+}$ , and each mole of $H^{+}$ interacts with one mole of ${OH}^{-}$ produced by the $K_{b}$ reaction.

As a result of these reactions, the $K_{b}$ reaction continues to the same extent as the $K_{a}$ reaction.

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Consider ${HA}^{-}$ , the intermediate form of a diprotic acid. $K_{2}$ for this species is $10^{- 4}$ and $K_{b}$ is $10^{- 8}$ . Nonetheless, the $K_{a}$ and $K_{b}$ reactions proceed to nearly the same extent when NaHA is dissolved in water. Explain.

Short Answer

Step by step solution

Definition of diprotic acid.

Explanation.

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Consider HA-, the intermediate form of a diprotic acid.K2for this species is10-4andKbis10-8. Nonetheless, the Kaand Kbreactions proceed to nearly the same extent when NaHA is dissolved in water. Explain.

Short Answer

Step by step solution

Definition of diprotic acid.

Explanation.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Nuclear Chemistry

The Earths Atmosphere

Ionic and Molecular Compounds

Chemistry Branches

Making Measurements

Kinetics

Study anywhere. Anytime. Across all devices.

Consider ${HA}^{-}$ , the intermediate form of a diprotic acid. $K_{2}$ for this species is $10^{- 4}$ and $K_{b}$ is $10^{- 8}$ . Nonetheless, the $K_{a}$ and $K_{b}$ reactions proceed to nearly the same extent when NaHA is dissolved in water. Explain.