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Chapter 10: Q4TY (page 221)

Compute the pH of $^{0.010 M}$ HHis.

Short Answer

Expert verified

The pH of $^{0.010 M His}$ is discovered to be $^{pH = 7.62}$ .

Step by step solution

01

Definition of Metallic elements and non metallic elements

The pH scale is a measurement of how acidic or al.
The pH scale was created to quantify the concentration of hydrogen ions in a solution, and the p in pH stands for 'potenz' in German.

02

Determine the pH of HHis.

The pH of $^{0.010 MH}$ His must be calculated.

The diprotic form's intermediate form

$[H^{+}] = \sqrt{\frac{K_{2} + K_{3} F + K_{2} K_{w}}{K_{2} + F}}$

The equilibrium constants that should be used are as follows $^{K_{2}}$ and $^{K_{3}}$ in place of and $^{K_{2}}$

0.10MHHis: it get 10-14 it follow the equation.

$[H^{+}] = \sqrt{\frac{(10^{5.97}) (10^{. 928}) (0.10) (10^{5.97}) (1.0 \times 10^{- 14})}{10^{5.97} + 0.10}} = 2.37 \times 10^{- 8} M pH = 7.62$

This is similar to $^{\frac{1}{2} ({pK}_{2} + {pK}_{3}) = 7.62}$

The pH ofis discovered to be $^{pH = 7.62}$

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Most popular questions from this chapter

The both $^{[H_{2} A] = [H A^{‐}]}$ are equal as found to be $^{pH = 10.54}$

(a) Derive equations for $α_{H_{3} A}, α_{H_{2} A}, α_{H A^{2 -}}, α_{A^{3 -}}$ for a triprotic system.

(b) Calculate the values of these fractions for phosphoric acid at pH 7.00.

What fraction of ethane-1,2-dithiol is in each form (H2A,HA2, A22) at pH 8.00? at pH 10.00?

$C O_{2} (g) 𝆏 C O_{2} (a q) K_{H} = \frac{[C O_{2} (a q)]}{P_{C O_{2}}} = 10^{- 1.2073} m o l k g^{- 1} b a r^{- 1} a t 0^{\circ} C = 10^{- 1.6048} m o l k g^{- 1} b a r^{- 1} a t 30^{\circ} C C O_{2} (a q) + H_{2} O 𝆏 H C O_{3}^{-} + H^{+} K_{a 1} = \frac{[H C O_{3}^{-}] [H^{+}]}{[C O_{2} (a q)]} = 10^{- 6.1004} m o l k g^{- 1} a t 0^{\circ} C = 10^{- 5.8008} m o l k g^{- 1} b a r^{- 1} a t 30^{\circ} C H C O_{3}^{-} 𝆏 C O_{3}^{2 -} + H^{+} C a C O_{3} (S, a r a g o n i t e) 𝆏 C a^{2 +} + C O_{3}^{- 2} K_{s p}^{a r g} = [C a^{2 +}] [C O_{3}^{2 -}] = 10^{- 6.1113} m o l^{2} k g^{- 2} b a r^{- 2} a t 0^{\circ} C = 10^{- 6.1391} m o l^{2} k g^{- 2} b a r^{- 2} a t 30^{\circ} C C a C O_{3} (s, c a l c i t e) 𝆏 C a^{2 +} + C O_{3}^{- 2} k_{s p}^{c a l} = [C a^{2 +}] [C O_{3}^{2 -}] = 10^{- 6.3652} m o l^{2} k g^{- 2} b a r^{- 2} a t 0^{\circ} C = 10^{- 6.3713} m o l^{2} k g^{- 2} b a r^{- 2} a t 30^{\circ} C$ Effect of temperature on carbonic acid acidity and the solubility of localid="1654949830957" ${CaCO}_{3} \times^{14} Box 10 - 1$ states that marine life withlocalid="1654949841354" ${CaCO}_{3}$ shells and skeletons will be threatened with extinction in cold polar waters

before that will happen in warm tropical waters. The following equilibrium constants apply to seawater at $0^{\circ}$ ndlocalid="1654949866125" $30^{\circ} C$ , when concentrations are measured in moles per kilogram of seawater and pressure is in bars:

localid="1654951136007" ${CO}_{2} (g) 𝆏 {CO}_{2} (aq) K_{H} = \frac{[{CO}_{2} (aq)]}{P_{{CO}_{2}}} = 10^{- 1.2073} mol {kg}^{- 1} {bar}^{- 1} at 0^{\circ} C = 10^{- 1.6048} mol {kg}^{- 1} {bar}^{- 1} at 30^{\circ} C {CO}_{2} (aq) + H_{2} O 𝆏 {HCO}_{3}^{-} + H^{+} K_{a 1} = \frac{[{HCO}_{3}^{-}] [H^{+}]}{[{CO}_{2} (aq)]} = 10^{- 6.1004} mol {kg}^{- 1} at 0^{\circ} C = 10^{- 5.8008} mol {kg}^{- 1} {bar}^{- 1} at 30^{\circ} C {HCO}_{3}^{-} 𝆏 {CO}_{3}^{2 -} + H^{+} {CaCO}_{3} (S, aragonite) 𝆏 {Ca}^{2 +} + {CO}_{3}^{- 2} K_{sp}^{\arg} = [{Ca}^{2 +}] [{CO}_{3}^{2 -}] = 10^{- 6.1113} {mol}^{2} {kg}^{- 2} {bar}^{- 2} at 0^{\circ} C = 10^{- 6.1391} {mol}^{2} {kg}^{- 2} {bar}^{- 2} at 30^{\circ} C {CaCO}_{3} (s, calcite) 𝆏 {Ca}^{2 +} + {CO}_{3}^{- 2} k_{sp}^{cal} = [{Ca}^{2 +}] [{CO}_{3}^{2 -}] = 10^{- 6.3652} {mol}^{2} {kg}^{- 2} {bar}^{- 2} at 0^{\circ} C = 10^{- 6.3713} {mol}^{2} {kg}^{- 2} {bar}^{- 2} at 30^{\circ} C$

The first equilibrium constant is calledlocalid="1654949908801" $K_{H}$ for Henry's law (Problem 10-10). Units are given to remind you what units you must use.

(a) Combine the expressions forlocalid="1654949922835" $K_{H}, K_{21}$ , andlocalid="1654949935065" $K_{22}$ to find an expression forlocalid="1654949944862" $[{CO}_{3}^{- 2}]$ in terms oflocalid="1654949958224" $P_{{CO}_{2}}$ andlocalid="1654949971486" $[H^{+}]$ .

(b) From the result of (a), calculatelocalid="1654949980228" $[{CO}_{3}^{2 -}] ({molkg}^{- 1})$ atlocalid="1654950000228" $p_{{CO}_{2}} = 800 μ$ bar and pH=7.8 at temperatures oflocalid="1654950013597" $0^{\circ}$ (polar ocean) andlocalid="1654950030147" $30^{\circ} C$ (tropical ocean). These are conditions that could possibly be reached around the year 2100 .

(c) The concentration oflocalid="1654950042348" ${Ca}^{2 +}$ in the ocean islocalid="1654950053646" $0.010 M$ . Predict whether aragonite and calcite will dissolve under the conditions in (b).

Find the pH and the concentration of each species of lysine in a solution of $^{0.010}$ 0 M lysine? HCl, lysine monohydrochloride. The notation “lysine? HCl” refers to a neutral lysine molecule that has takenon one extra proton by addition of one mole of HCl. A more meaning-

ful notation shows the salt (lysineH1)( $^{C 12}$ ) formed in the reaction..

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