Chapter 10: QCE (page 229)

How many milliliters of $0.800 M KOH$ should be added to $5.02 g$ of 1,5 -pentane dioic acid $(C_{5} H_{8} O_{4,} FM$ 132.11) to give a pH of ^4.40 when diluted to 250mL ?

Short Answer

Expert verified

The required volume of KOH solution is 25.2mL .

Step by step solution

Define the Henderson-Hasselbalch equation

The relationship between pH and pKa(acid dissociation constant) of acids in aqueous solutions is described by the Henderson-Hasselbalch equation. This equation can be used to forecast the pH of a buffer solution when the concentrations of such acid as well as its conjugate base, or the base and the related conjugate acid, are determined.

Formula to be used: $pH = {pKK}_{1} + \log \frac{|{HA}^{-}|}{|H_{2} A|}$

Step 2:Calculate the volume of KOH solution required

The solution is an equal mixture of the $H_{2} A_{and {HA}^{-}}$

When creatingthemixture of solutions that requiresa quantity of KOH to be added to convert $H_{2} {AtoHA}^{-}$ ,

$pH = 4.40 and 0.0380 {molH}_{2} A pH = {pK}_{1} + \log \frac{|{HA}^{-}|}{[H_{2} A |} 4.4 = 4.345 + \log \frac{x}{0.0380 - x} = x = 0.0202 mol = \frac{(0.0202 mol)}{(0.800 M)}$

Thus, the required volume of KOH solution is 25.2mL

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How many milliliters of $0.800 M KOH$ should be added to $5.02 g$ of 1,5 -pentane dioic acid $(C_{5} H_{8} O_{4,} FM$ 132.11) to give a pH of ^4.40 when diluted to 250mL ?

Short Answer

Step by step solution

Define the Henderson-Hasselbalch equation

Step 2:Calculate the volume of KOH solution required

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How many milliliters of 0.800MKOHshould be added to 5.02gof 1,5 -pentane dioic acid (C5H8O4,FM132.11) to give a pH of 4.40 when diluted to 250mL ?

Short Answer

Step by step solution

Define the Henderson-Hasselbalch equation

Step 2:Calculate the volume of KOH solution required

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemistry Branches

The Earths Atmosphere

Nuclear Chemistry

Kinetics

Chemical Analysis

Inorganic Chemistry

Study anywhere. Anytime. Across all devices.

How many milliliters of $0.800 M KOH$ should be added to $5.02 g$ of 1,5 -pentane dioic acid $(C_{5} H_{8} O_{4,} FM$ 132.11) to give a pH of ^4.40 when diluted to 250mL ?