Standard addition graph. Allicin is a $\mathbf{~}\mathbf{0}\mathbf{.}\mathbf{4}\mathbf{wt}\mathbf{\%}$component in garlic with antimicrobial and possibly anticancer and antioxidant activity. It is unstable and therefore difficult to measure. An assay was developed in which the stable precursor alliin is added to freshly crushed garlic and converted to allicin by the enzyme alliinase found in garlic. Components of the garlic are extracted and measured by chromatography. The chromatogram shows standard additions reported as mg alliin added per gram of garlic. The chromatographic peak is allicin from the conversion of alliin.

(a)The standard addition procedure has a constant total volume. Measure the responses in the figure and prepare a graph to find how much alliin equivalent was in the unspiked garlic. The units of your answer will be mg alliin/g garlic. Find the $\mathbf{95}\mathbf{\%}$confidence interval, as well.

(b) Given that$\mathbf{2}\mathbf{mol}$of alliin are converted to$\mathbf{1}\mathbf{mol}$of allicin, find the allicin content of garlic (mg allicin/g garlic) including the$\mathbf{95}\mathbf{\%}$confidence interval.

Allicin is a $~0.4\mathrm{wt}\%$

component in garlic with antimicrobial

The chromatographic peak is allicin from the conversion of alliin.

$95\%$of confidence interval have to be found.

$2\mathrm{mol}$of alliin are converted to $1\mathrm{mol}$of allicin

It is necessary to graph the allilin equivalent in unspiked garlic and get the $95\%$

confidence interval.

Concept introduction:

The graph will be drawn using the below equation: role="math" localid="1654855448601" $\mathrm{Plot}\underset{\mathrm{Function}\mathrm{to}\mathrm{plot}\mathrm{on}\mathrm{y}-\mathrm{axis}}{\underbrace{{\mathrm{l}}_{\mathrm{s}+\mathrm{x}}+\mathrm{X}\left(\frac{\mathrm{V}}{{\mathrm{V}}_0}\right)}}$$\mathrm{versus}{\mathrm{l}}_{\mathrm{x}}+\frac{{\mathrm{l}}_{\mathrm{x}}}{{\left[\mathrm{X}\right]}_{\mathrm{i}}}$$\underset{\mathrm{function}\mathrm{to}\mathrm{plot}\mathrm{on}\mathrm{x}-\mathrm{axis}}{\underbrace{{\left[\mathrm{S}\right]}_{\mathrm{i}}\left(\frac{{\mathrm{V}}_{\mathrm{s}}}{{\mathrm{V}}_0}\right)}}$

Here$\mathrm{X}-$intercept is${\left[\mathrm{X}\right]}_{\mathrm{i}}$

(a)

The allilin equivalent in unspiked garlic had to be graphed, and the $95\%$confidence interval was computed as $8.21\pm 0.62\mathrm{mg}\mathrm{alliin}/\mathrm{g}.$

In the above spreadsheet $\mathrm{x}-\mathrm{axis}$has spike $\left(\mathrm{mg}/\mathrm{g}\right)\mathrm{and}{\mathrm{l}}_{\mathrm{s}+\mathrm{x}}$are plotted.

Figure 2 shows $\mathrm{X}-\mathrm{intercept}$$=\frac{-\mathrm{b}}{\mathrm{m}}=8.20006$is the standard deviation of localid="1654856621530" $\mathrm{X}-\mathrm{intercept}=8.21\pm 0.62\mathrm{mg}\mathrm{alliing}/\mathrm{g}\mathrm{garlic}.$

The allilin equivalent in unspiked garlic was graphed, and the$95\%$confidence interval was estimated as$8.21\pm 0.62\mathrm{mg}\mathrm{alliing}/\mathrm{g}\mathrm{garlic}.$

(b)

Interpretation Introduction

Interpretation:

When $2\mathrm{mol}$of alliin is converted to $1\mathrm{mol}$, the allicin content of garlic $\left(\mathrm{mg}\mathrm{alliin}/\mathrm{g}\mathrm{garlic}\right)$must be computed.

In the first figure, $\mathrm{preadsheetx}-\mathrm{axis}$has spike $\left(\mathrm{mg}/\mathrm{g}\right)\mathrm{and}{\mathrm{l}}_{\mathrm{s}+\mathrm{x}}$are plotted.

In the figure 3,the quantity of allicin in garlic ,when one mole of allicin is given by two moles of allin is:

$\frac{1}{2}\left(162.3/177.3\right)\left(8.21\pm 0.62\mathrm{mg}\right)=3.76\pm 0.28\mathrm{mg}\mathrm{alliicin}/\mathrm{g}$

The amount of allicin in garlic was determined as $3.8\pm 0.3\mathrm{mg}\mathrm{allicin}/\mathrm{g}.$