Consider a sample that contains analyte at the detection limit defined in Figure. Explain the following statements: There is approximately a 1%chance of falsely concluding that a sample containing no analyte contains analyte above the detection limit. There is a50%chance of concluding that a sample that really contains analyte at the detection limit does not contain analyte above the detection limit.

Short Answer

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The following statements was explained.

1. Above the detection limit approximately

1%

chance of falsely concluding that the sample does contain no analyte.

2. Above the detection limit approximately50%chance of concluding that the sample doesn't contains analyte.

Step by step solution

01

The detection limit

The concentration of an analyte that produces a signal with a standard deviation three times that of a blank signal.

The minimum detectable concentration =3sm

Where,

S=Standard deviation.

m=Slope of linear calibration curve.

02

Explanation of statements

The first statement means that since there is approximately 1%chance of false negative results showing up, there will also be approximately 1%of samples (that do NOT contain the analytes) that will respond with a signal above the detection limit.

For the second statement -- which is a hypothetical situation for false positive results -- means that50% of the samples containing the analyte with a signal going below the limit of detection.

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