The pathogenic bacterium Salmonella enterica uses tetrathionate found in the human gut as an oxidant- just as we useO2to metabolize our food. Write the half-reaction in which tetrathionate serves as an oxidant. Is tetrathionate as powerful an oxidant asO2?

Short Answer

Expert verified

The half reaction of tetrathionate as an oxidant is,

S4O62-+2e2S2O32

Step by step solution

01

Definition of redox titration

  • Redox reactions are oxidation-reduction chemical reactions in which the oxidation states of the reactants change. The term redox refers to the reduction-oxidation process.
  • In a redox reaction, or Oxidation-Reduction process, the oxidation and reduction reactions always happen at the same time.
02

Determine the half reaction in which tetrathionate as an oxidant.

Half reaction of tetrathionate as an oxidant:

S4O62-+2e2S2O32E0=0.080V

Half reaction of oxygen as an oxidant:

12O2+2H+2e-H2OE0=1.23V

Values of standard reduction potential for each reaction can be found in appendix H. Since oxygen has a higher potential value it is a stronger oxidant than tetrathionate.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Warning! The Surgeon General has determined that this problem is hazardous to your health. The oxidation numbers of CUand Biin high-temperature superconductors of the type Bi2Sr2(Ca0xYa2)Cu2Ox(which could contain Cu2+,Cu3+,Bi3+ and Bi3+) can be measured by the following procedure. In Experiment, the superconductor is dissolved in 1MHClcontaining excess 2mMCuCl2Bi5+(written as BiO3-) and Cu3+ consume Cu+ to make Cu2+:

BiO3+2Cu++4H+BiO++2Cu2++2H2OCu3++Cu+2Cu2+

The excess, unreactedCu4is then titrated by coulometry (described in Chapter). In Experiment , the superconductor is dissolved in1mMFeCl24H2Ocontaining excessBi5+. reacts with therole="math" localid="1668352055227" Fe2+ butCu3+ does not react withdata-custom-editor="chemistry" Fe2+41.

role="math" localid="1668352140519" BiO3+2Fe2++4H+BiO++2Fe3++2H2OCu3++12H2OCu2++14O2+H+

The excess, unreacted is then titrated by coulometry. The total oxidation number of is measured in Experiment, and the oxidation number ofis determined in Experiment. The difference gives the oxidation number of.

(a) In Experiment AA2, a sample of Bi2Sr2CaCu2O5(FM760.37+15.9994x)(containing no yttrium) weighing 102.3mg was dissolved in 100.0mLof 1MHCl containing 2.000mMCuCl. After reaction with the superconductor, coulometry detected 0.1085 mmolof unreactedCu+ in the solution. In Experiment B, 94.6 mgof superconductor were dissolved in 100.0mL. of 1MHCl containing1.000mMFeCl-4H2O. After reaction with the superconductor, coulometry detected 0.0577 mmolof unreacted. Find the average oxidation numbers of Biand Cuin the superconductor and the oxygen stoichiometry coefficient, x.

(b) Find the uncertainties in the oxidation numbers and x if the quantities in Experiment Aare102.3(±0.2)mgand0.1085(±0.0007)mmoland the quantities in Experiment Bare94.6(±0.2)me and0.0577(±0.0007)mmol. Assume negligible uncertainty in other quantities.

Write balanced half-reactions in which MnO4-acts as an oxidant at

(a)pH=0;(b)pH=10;(c)pH=15.

A 3.026-g portion of a copper(II) salt was dissolved in a 250-mL volumetric flask. A 50.0-mL aliquot was analyzed by adding of KI and titrating the liberated iodine with 23.33mL of 0.04668MNa2S2O3Find the weight percent of Cu in the salt. Should starch indicator be added to this titration at the beginning or just before the end point?

Would Tris (2,2'-bipyridine)iron be a useful indicator for the titration of Sn2with Mn(EDTA)? (Hint: The potential at the equivalence point must be between the potentials for each redox couple)

State two ways to make standard triiodide solution.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free