Calculate the power per unit area (the exitance, W/m2) radiating from a blackbody at 77 K (liquid nitrogen temperature) and at 298 K (room temperature).

Short Answer

Expert verified

The value of Planck distribution at 77k and 298k

M=1.99w/m2;M=447.13W/m22

Step by step solution

01

Step1:Define planck distribution:

Planck's law describes the unique and characteristic spectral distribution for electromagnetic radiation in thermodynamic equilibrium, when there is no net flow of matter or energy

02

Step 2:Calculating the power unit:

The existence is:M=σ.T4

ForT=77K:M=5.6698.10-8.10W/m2K4.77K4

M=1.99W/m2

ForT=298k:M=5.6698.10-8W/m2k4.298K4

M=447.13W/m2

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