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Chapter 20: Q17P (page 526)

Light passes from benzene (medium1)to water (medium 2) in Figure 20at (a)θ1=30°or (b)θ1=0°. Find the angleθ2in each case.

Short Answer

Expert verified

a) Forθ1=30°θ2=34.33,

b) For θ1=0°θ2=0°,.

Step by step solution

01

Concept used.

The Snell's law is:

n1‐sinθ1=n2‐sinθ2.

02

Find the angle θ2 in θ1=30°

a)

Consider the angleθ1=30° that is made by light when it passes from benzene to water.

The angleθ2is:

1.50·sin30°=1.33·sinθ2sinθ2=1.50·sin30°1.33sinθ2=0.56391θ2=34.33°

03

Find the angle θ2 is θ1=0°

b)

An angleθ1=0° is made by light when it passes from benzene to water.

The angle θ2is:

1.50·sin0°=1.33·sinθ2sinθ2=1.50·sin30°1.33sinθ2=0θ2=0°

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The true absorbance of a sample is 1.000, but the mono chromator passes 1.0% stray light. Add the light coming through the sample to the stray light to find the apparent transmittance of the sample. Convert this answer back into absorbance and find the relative error in the calculated concentration of the sample.

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