Light passes from benzene (medium1)to water (medium 2) in Figure 20at (a)θ1=30°or (b)θ1=0°. Find the angleθ2in each case.

Short Answer

Expert verified

a) Forθ1=30°θ2=34.33,

b) For θ1=0°θ2=0°,.

Step by step solution

01

Concept used.

The Snell's law is:

n1sinθ1=n2sinθ2.

02

Find the angle θ2 in θ1=30°

a)

Consider the angleθ1=30° that is made by light when it passes from benzene to water.

The angleθ2is:

1.50·sin30°=1.33·sinθ2sinθ2=1.50·sin30°1.33sinθ2=0.56391θ2=34.33°

03

Find the angle θ2 is θ1=0°

b)

An angleθ1=0° is made by light when it passes from benzene to water.

The angle θ2is:

1.50·sin0°=1.33·sinθ2sinθ2=1.50·sin30°1.33sinθ2=0θ2=0°

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