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Chapter 20: Q20AE (page 524)

The true absorbance of a sample is 1.000, but the mono chromator passes 1.0% stray light. Add the light coming through the sample to the stray light to find the apparent transmittance of the sample. Convert this answer back into absorbance and find the relative error in the calculated concentration of the sample.

Short Answer

Expert verified

The absorbance is 0.9629.

Step by step solution

01

Calculate the apparent Transmittence:

Given,

The true absorbance of a sample is 1.000, but 1.0 % stray light reaches the detector.

The apparent transmittance can be calculated as

True transmittance=10-1.000=0.100 with 1.0 % stray light, the apparent transmittance is

P+SP0+S=0.100+0.0101+0.010=0.111.01=0.1089

02

Step:2  Apparent absorbence:

The apparent absorbance can be calculated using -log T

-log0.1089

= 0.9629

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The true absorbance of a sample is 1.000, but the mono chromator passes 1.0% stray light. Add the light coming through the sample to the stray light to find the apparent transmittance of the sample. Convert this answer back into absorbance and find the relative error in the calculated concentration of the sample.
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