Explain why the transmission spectrum is calculated from the quotient (sample transform) M(background transform) instead of the difference (sample transform) - (background transform).

Short Answer

Expert verified

The transmittance spectrum was explained using the quotient (sample transform / background transform) rather than the difference (sample transform) (background transform).

Step by step solution

01

Definition of transmission spectrum

  • Because more light is passed through the sample, the maximum intensities of a transmission spectrum will be at wavelengths where the absorption is weakest.
  • The maximum intensities in an absorption spectrum occur at wavelengths where the absorption is strongest.
02

Determine the transmission spectrum is calculated from the quotient (sample transform) M (background transform) instead of the difference (sample transform) - (background transform).

  • The transmittance spectrum must be stated using the quotient (sample transform / background transform) rather than the difference (sample transform) (background transform).
  • The background correction is a measurement of the sample's transmittance by comparing it to the backdrop's transmittance, which is utilised in the background correction.
  • The background transform observes the incident irradiance Po, while the sample transform observes the transmitted irradiance P.
  • As a result, the transmittance is,PPo notPPo
  • The transmittance spectrum was explained using the quotient (sample transform / background transform) rather than the difference (sample transform) (background transform).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that a grating with 103 grooves/cm provides a dispersion of 5.88 per mm of wavelength if n 5 1 and f 5 108 in Equation 20-4.

Here is an extremely sensitive method for measuring nitrite () down to in natural waters. The water sample is treated with sulfanilamide and N-(1-naphthylethylenediamine) in acid solution to produce a colored product with a molar absorptivity of 4.5×104M-1cm-1at 540 nm. The colored solution is pumped into a 4.5-meter-long, coiled Teflon tube whose fluorocarbon wall has a refractive index of 1.29. The aqueous solution inside the tube has a refractive index near 1.33. The colored solution is pumped through the coiled tube. An optical fiber delivers white light into one end of the tube, and an optical fiber at the other end leads to a polychromator and detector.

(a) Explain the purpose of the coiled Teflon tube and explain how it functions.

(b) What is the critical angle of incidence for total internal reflection at the Teflon/water interface?

(c) What is the predicted absorbance of a1.0nM solution of colored reagent?

The variation of refractive index, n, with wavelength for fused silica is given by

n21=(0.6961663)λ2λ2(0.0684043)2+(0.4079426)λ2λ2(0.1162414)2+(0.8974794)λ2λ2(9.896161)2

where λ is expressed in μm.

(a) Make a graph of n versus λ with points at the following wavelengths: 0.2,0.4,0.6,0.8,1,2,3,4,5, and 6μm.

(b) The ability of a prism to spread apart (disperse) neighboring wavelengths increases as the slope dn/increases. Is the dispersion of fused silica greater for blue light or red light?

A spectrum has a signal-to-noise ratio of 8/1. How many spectra must be averaged to increase the signal-to-noise ratio to 20 / 1?

The prism shown here is used to totally reflect light at a90°angle. No surface of this prism is silvered. Use Snell's law to explain why total reflection occurs. What is the minimum refractive index of the prism for total reflection?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free