Which variables increase the resolution of a grating? Which variables increase the dispersion of the grating? How is the blaze angle chosen to optimize a grating for a particular wavelength?

Short Answer

Expert verified

The number of grooves that are illuminated and the diffraction order increases the resolution of a grating.

Step by step solution

01

Step: 1 Define the grating:

Diffraction grating is a series of clusters used to separate an incident wave into its wavelength by directly separating the magnitude of the diffraction.

02

Step: 2 The variables which increase the resolution of a grating:

The number of grooves that are illuminated and the diffraction order increases the resolution of a grating.

03

Step: 3 The variables which increase the dispersion of the grating:

The diffraction order increase the dispersion of the grating, while the spacing between lines in the grating is inversely proportional to dispersion of the grating.

04

Step: 4 The blaze angle chosen to optimize a grating:

The blaze angle chosen to optimize a grating for a particular wavelength is selected to give specular reflection at desired diffraction angle.

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Most popular questions from this chapter

The exitance (power per unit area per unit wavelength) from a blackbody (Box 20-1) is given by the Planck distribution: Mλ=2πhc2λ5(1ehc/Akt-1)where λis wavelength, Tis temperature K), his Planck’s constant, Cis the speed of light, and kis Boltzmann’s constant. The area under each curve between two wavelengths in the blackbody graph in Box 20-1is equal to the power per unit area(W/m2)emitted between those two wavelengths. We find the area by integrating the Planck function between wavelengthsλ1andλ2

role="math" localid="1664862982839" Poweremitted=λ1λ2Mλ

For a narrow wavelength range, λ1the value of Mλis nearly constant and the power emitted is simply the product Mλλ2.

(a) Evaluate Mhatλ=2.00μmand atλ=10.00μmatT=1000K

(b) Calculate the power emitted per square meter atin the intervalby evaluating the product

(c) Repeat part (b) for the interval9.99to10.01μm

(d) The quantityM2μm/M10μmis the relative exitance at the two wavelengths. Compare the relative exitance at these two wave-lengths atwith the relative exitance at 100K. What does your answer mean?

(a) In the cavity ring-down measurement at the opening of this chapter, absorbance is given by A=Lcln10(1τ-1τ0)whereis the length of the triangular path in the cavity, Cis the speed of light, Tis the ring-down lifetime with sample in the cavity, and T0is the ring-down lifetime with no sample in the cavity. Ring-down lifetime is obtained by fitting the observed ring-down signal intensityto an exponential decay of the form l=l0e-, whereis the initial intensity and t is time. A measurement ofis made at a wavelength absorbed by the molecule. The ring-down lifetime for 21.0-cm-1 along empty cavity is 18.52μsand18.52μsfor a cavity containing.role="math" localid="1664865078479" CO2 Find the absorbance ofCO2at this wavelength.

(b) The ring-down spectrum below arises from CH413and CH412from 1.9ppm(vol/yol)of methane in outdoor air at 0.13. The spectrum arises from individual rotational transitions of the ground vibrational state to a second excited C-H)vibrational state of the molecule. (i) Explain what quantity is plotted on the ordinate ( Y-axis). (ii) The peak forCH412is at6046.9546cm-1. What is the wavelength of this peak in? What is the name of the spectral region where this peak is found?

(a) What resolution is required for a diffraction grating to resolve wavelengths of 512.23 and 512.26 nm? (b) With a resolution of 104, how close in nm is the closest line to 512.23 nm that can barely be resolved? (c) Calculate the fourth-order resolution of a grating that is 8.00 cm long and is ruled at 185 lines/mm. (d) Find the angular dispersion (ϕ) between light rays with wavelengths of 512.23 and 512.26 nm for first-order diffraction (n 5 1) and thirtieth-order diffraction from a grating with 250 lines/mm and f 5 3.08.

Consider a reflection grating operating with an incident angle of 408 in Figure 20-7. (a) How many lines per centimeter should be etched in the grating if the first-order diffraction angle for 600 nm (visible) light is to be 2308? (b) Answer the same question for 1 000 cm21 (infrared) light.

Refer to the Fourier transform infrared spectrum in Figure 20-33.

(a) The interferogram was sampled at retardation intervals of1.2260×10-4cm. What is the theoretical wavenumber range (0 to ?) of the

spectrum?

(b) A total of 4 096 data points were collected from δ=-toδ=+. Compute the value of, the maximum retardation.

(c) Calculate the approximate resolution of the spectrum.

(d) The interferometer mirror velocity is given in the figure caption. How many microseconds elapse between each datum?

(e) How many seconds were required to record each interfero gram once?

(f) What kind of beam splitter is typically used for the region 400 to 4 000cm-1? Why is the region below 400cm-1not observed?

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