Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 0: Q11P (page 1)

Titration of metal ion with EDTA. Use Equation 12-11 to compute curves (pM versus mL of EDTA added) for the titration of 10.00 mL of 1.00 mM M2+ (= Cd2+ or Cu2+) with 10.0 mM EDTA at pH 5.00. Plot both curves on one graph.

Short Answer

Expert verified

The curves for both the metals Cd and Cu are shown below

Step by step solution

01

Information given

Titration of 10.0 mL of 1.0mM M2+ with 10 mM EDTA. The titration should be carried out at pH=5.00.

02

Equation need to be used to develop spreadsheet

Using Equation 12-11 the equation for the fraction of titration of metal ion with EDTA is as follows

ϕCLVLCMVM=1+KfM-M+KfM2CMKfM+M+KfM2CL

Other formulas need to be used

M=10-pM

Here instead of formation constant (Kf), conditional formation constant Kfshould be taken in the above formula stated.

From table 12-1 the value of aY4for EDTA at 250C and pH 5 is 2.9×10-7

From table 12-2 we get log Kffor Cu2+= 18.78

From table 12-2 we get log Kf for Cd2+= 16.5

03

Spreadsheet

Spreadsheets developed are shown below

04

Graph Plot

The curves for both the metals Cd and Cu are shown below

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) What is the difference between absorption and adsorption?

(b) How is an inclusion different from an occlusion?

The metal ion indicator xylenol orange (Table 12-3) is yellow atpH6(λmax=439nm).The spectral changes that occur asVO2+is added to the indicator atpH6 are shown here. The mole ratioVO2+/xylenol orange at each point is


Suggest a sequence of chemical reactions to explain the spectral changes, especially the isosbestic points at457 and 528nm.

Absorption spectra for the reaction of xylenol orange withVO2+atpH 6.0

A solid mixture weighing 0.05485 gcontained only ferrous ammonium sulphate and ferrous chloride. The sample was dissolved in1MH2SO4, and the Fe2+required 13.39 mL oflocalid="1663577431957" 0.01234MCe4+for complete oxidation to localid="1663577453691" Fe3+. Calculate the weight percent of Cl in the original sample. If you need refreshing, see Section 7-2 for an example of a titration of a mixture.

localid="1663574328546" FeSO4×(NH4)2SO4×6H2OFeCI2×6H2O

Ferrous ammonium sulfate Ferrous chloride

FM 392.13

FM 234.84

(a) Figure 1-1 shows a peak O3concentration of 13mPain the stratosphere. Figure 1-3 shows a peak concentration of O3 of 39ppbat ground level at one particular location. To compare these concentrations, convertto pressure in. Which concentration is higher? To convert 39ppb to, assume that atmospheric pressure at the surface of the Earth is 1 bar =105Pa. If atmospheric pressure is 1 bar, then a concentration ofis.

(b) The pressure of the atmosphere at 16kmaltitude in the stratosphere is 9.6kPa. The peak pressure O3 ofat this altitude in the stratosphere in Figure 1-1 is 19mPa. Convert the pressure of 19mPa toppb when the atmospheric pressure is 9.6kPa

Write the chemical formula of a compound with a negative pK
See all solutions

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Read Explanation

Making Measurements

Read Explanation

Inorganic Chemistry

Read Explanation

Chemistry Branches

Read Explanation

The Earths Atmosphere

Read Explanation

Kinetics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free