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Chapter 0: Q17P (page 1)

How many milliliters of 2.15% alcoholic dimethylglyoxime should be used to provide a 50.0% excess for Reaction 27-7 with 0.998 4 g of steel containing 2.07 wt% Ni? Assume that the density of the dimethylglyoxime solution is 0.790 g/mL.

Short Answer

Expert verified

The value of volume of DGM of 2.15% is V=7.22 mL

Step by step solution

01

Find mass of solution for 0.1277g:

Calculate m(Ni) and n,

m(Ni)=wt%×0.9984gm(Ni)=0.0207×0.9984g)

m(Ni)=0.02067gn(Ni)=m/M=3.521×104mol

From this we can find m(DGM),

m(DGM)=n×Mm(DGM)=2(3.521×10-4mol)×116.12g/molm(DGM)=0.08177g

Calculate the 50% excess masss,

excess=1.5×0.08177gexcess=0.1227g

From this we can calculate the mass of solution,

m(solution)=excess0.0215gm(solution)=0.1227g/0.0215g

The mass of solution ism(solution)=5.705g

02

Calculate the volume of DGM of 2.15%:

V=m/ρV=5.705g/0.790g/mL

The value of volume of DGM of 2.15% isV=7.22mL

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