Chapter 0: Q4P (page 1)

The metal ion indicator xylenol orange (Table 12-3) is yellow at $pH 6 (λ_{\max} = 439 nm)$ .The spectral changes that occur as ${VO}^{2 +}$ is added to the indicator atpH6 are shown here. The mole ratio ${VO}^{2 +}$ /xylenol orange at each point is
Suggest a sequence of chemical reactions to explain the spectral changes, especially the isosbestic points at 457 and 528nm.
Absorption spectra for the reaction of xylenol orange with ${VO}^{2 +}$ atpH 6.0

Short Answer

Expert verified

A sequence of chemical reactions to explain the spectral changes, especially the isosbestic points at 457 and 528nm is

$X ({VO}^{2 +}) + Y (xylenol orange) \to XY XY + X \to X_{2} Y$

Step by step solution

Define isosbestic point:

During the physical change or chemical change, the total absorbance sample will not change and it will have a specific wavelength or frequency is called isosbestic points.

Determine the sequence of chemical reactions from the given isosbestic points:

Hence, when ${VO}^{2 +}$ is added, corresponding to the traces1-9,the peak at 439nm decreases while one arises at 485nm with isosbestic points at 457nm.

Observe the traces 10-16, the peak at 485nm decreases while one arises at 566 nm with isosbestic point at 528nm.

Thus, we write the reaction as,

$X ({VO}^{2 +}) + Y (xylenol orange) \to XY XY + X \to X_{2} Y$

Therefore, the sequences of chemical reaction about the spectral changes are,

$X ({VO}^{2 +}) + Y (xylenol orange) \to XY XY + X \to X_{2} Y$

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Short Answer

Step by step solution

Define isosbestic point:

Determine the sequence of chemical reactions from the given isosbestic points:

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