Chapter 0: Q6P (page 9)

The iodide $(I^{-})$ content of a commercial mineral water was measured by two methods that produced wildly different results. Method A found $^{0.23}$ milligrams of $(I^{-})$ per liter $(m g / L)$ and method B found 0.009mg/L. When ${Mn}^{2 +}$ was added to the water, the $I^{-}$ content found by method A increased each time that more ${Mn}^{2 +}$ was added, but results from method B were unchanged. Which of the Terms to Understand describes what is occurring in these measurements? Explain your answer. Which result is more reliable?

Short Answer

Expert verified

Method A gives a higher result than method B even when no ${Mn}^{2 +}$ is deliberately added.

Step by step solution

About iodide concentration

A commercial mineral water's iodide $(I^{-})$ concentration can be measured using two procedures (method A and method B), both of which can yield different findings.

Difference between a homogeneous materialand a heterogeneous material

In the $I^{-}$ analysis by method A, we seean interference from ${Mn}^{2 +}$
The presence of ${Mn}^{2 +}$ has an impact on the result of the $I^{-}$ analysis.
The apparent concentration of $I^{-}$ found by method A increases when the concentration of ${Mn}^{2 +}$ in the mineral water increases.
Since method B is not affected by the same interference, the concentration of $I^{-}$ is low and unaffected by the addition of ${Mn}^{2 +}$
Even when no ${Mn}^{2 +}$ is intentionally added, approach A gives a better outcome than method Bsince there mustbe some ${Mn}^{2 +}$ in the original mineral water.

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Short Answer

Step by step solution

About iodide concentration

Difference between a homogeneous materialand a heterogeneous material

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