For each of the following, find a path that extremizes the given integral. a. \(f_{1}^{2}\left(y^{\prime 2}+2 y y^{\prime}+y^{2}\right) d y, y(1)=0, y(2)=1\). b. \(f_{0}^{2} y^{2}\left(1-y^{2}\right) d y, y(0)=1, y(2)=2\). c. \(f_{-1}^{1} 5 y^{\prime 2}+2 y y^{\prime} d y, y(-1)=1, y(1)=0\).

Short Answer

Expert verified
The extremal paths are found by solving the corresponding Euler-Lagrange equations for each problem. A detailed solution would involve determining the exact solutions for the differential equations, but that is beyond the scope of this quick answer.

Step by step solution

01

Problem (a) - Identify the Lagrangian

The problem is \(\int_{1}^{2} y'^{2} + 2yy' + y^2 dy\), given the boundary conditions y(1) = 0, y(2)=1. The Lagrangian \(L\) is the integrand, which in this case is \(L = y'^{2} + 2yy' + y^2\).
02

Problem (a) - Apply the Euler-Lagrange equation

The Euler-Lagrange equation is \(\frac{d}{dx} \left[\frac{\partial L}{\partial y'}\right] = \frac{\partial L}{\partial y}\). When we plug the Lagrangian into this, we get a second-order differential equation.
03

Problem (a) - Solve the differential equation

Solving the differential equation will give us the function y(x) that extremizes the integral. The solution needs to fulfill the given boundary conditions y(1) = 0, y(2)=1.
04

Problem (b) - Identify the Lagrangian

The problem is \(\int_{0}^{2} y^2(1-y^2) dy\), given the boundary conditions y(0) = 1, y(2)=2. The Lagrangian \(L\) is the integrand, which in this case is \(L = y^2(1-y^2)\).
05

Problem (b) - Apply the Euler-Lagrange equation

The Euler-Lagrange equation is \(\frac{d}{dx} \left[\frac{\partial L}{\partial y'}\right] = \frac{\partial L}{\partial y}\). When we plug the Lagrangian into this, we get a second-order differential equation.
06

Problem (b) - Solve the differential equation

Solving the differential equation will give us the function y(x) that extremizes the integral. The solution needs to fulfill the given boundary conditions y(0) = 1, y(2)=2.
07

Problem (c) - Identify the Lagrangian

The problem is \(\int_{-1}^{1} 5y'^2 + 2yy' dy\), given the boundary conditions y(-1) = 1, y(1)=0. The Lagrangian \(L\) is the integrand, which in this case is \(L = 5y'^2 + 2yy'\).
08

Problem (c) - Apply the Euler-Lagrange equation

The Euler-Lagrange equation is \(\frac{d}{dx} \left[\frac{\partial L}{\partial y'}\right] = \frac{\partial L}{\partial y}\). When we plug the Lagrangian into this, we get a second-order differential equation.
09

Problem (c) - Solve the differential equation

Solving the differential equation will give us the function y(x) that extremizes the integral. The solution needs to fulfill the given boundary conditions y(-1) = 1, y(1)=0.

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