Find the general solution of the given equation by the method given. a. \(y^{\prime \prime}-3 y^{\prime}+2 y=10\). Method of Undetermined Coefficients. b. \(y^{\prime \prime}+y^{\prime}=3 x^{2}\). Variation of Parameters.

Short Answer

Expert verified
For part a, the general solution is \(y = c_{1} e^{x} + c_{2} e^{2x} + 5\). For part b, the general solution is \(y = c_{1} + c_{2} e^{-x} - x^2 e^{x} + 2x e^{x} - 2 e^{x}\).

Step by step solution

01

Part a: Find Homogeneous Solution

First, find the homogeneous solution \(y_{h}\) of the equation \(y^{\prime \prime}-3 y^{\prime}+2 y=0\). This is done by solving its characteristic equation \(r^2 - 3r + 2 = 0\) yielding \(r = 1, 2\) and hence \(y_{h} = c_{1} e^{x} + c_{2} e^{2x}\).
02

Part a: Find Particular Solution

Next step is to find the particular solution \(y_{p}\) using the method of Undetermined Coefficients. By inspection of the RHS of the given equation, we select \(y_p = A\) as our guess since RHS is a constant. Substituting \(y_p = A\) into the given equation gives \(A = 5\), so \(y_p = 5\).
03

Part a: Combine Solutions to Find General Solution

The general solution is the sum of the homogeneous solution and the particular solution, hence \(y = y_h + y_p = c_{1} e^{x} + c_{2} e^{2x} + 5\).
04

Part b: Find Homogeneous Solution

First, find the homogeneous solution of the equation \(y^{\prime \prime}+y^{\prime}= 0\). The characteristic equation for the homogeneous equation \(r^{2} + r = 0\) yields \(r = -1, 0\), which gives \(y_{h} = c_{1} + c_{2} e^{-x}\).
05

Part b: Use Variation of Parameters to Find Particular Solution

Use the method of variation of parameters to find the particular solution \(y_p\). The Wronskian of the homogeneous equations is given by \(W = -e^{-x}\) and the particular solution will be \(y_p = - \int x^2 e^x dx = -x^2 e^{x} + 2x e^{x} - 2 e^{x}\).
06

Part b: Combine Solutions to Find General Solution

Combine the homogeneous solution and the particular solution to get the general solution, hence \(y = y_h + y_p = c_{1} + c_{2} e^{-x} - x^2 e^{x} + 2x e^{x} - 2 e^{x}\).

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Most popular questions from this chapter

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