For each problem, determine equilibrium points, bifurcation points, and construct a bifurcation diagram. Discuss the different behaviors in each system. a. \(y^{\prime}=y-\mu y^{2}\) b. \(y^{\prime}=y(\mu-y)(\mu-2 y)\) c. \(x^{\prime}=\mu-x^{3}\) d. \(x^{\prime}=x-\frac{\mu x}{1+x^{2}}\).

Short Answer

Expert verified
a) Equilibrium points: \(y=0\), \(y=\mu\). Bifurcations occur at these points. b) Equilibrium points: \(y=0\), \(y=\mu\), \(y=\mu/2\). Bifurcations occur at these points. c) Equilibrium points: \(x=\sqrt[3]{\mu}\), \(x=-\sqrt[3]{\mu/2}\), \(x= \sqrt[3]{\mu/2}\). Bifurcations occur at these points. d) Equilibrium points: \(x=0\) and \(x=\sqrt{\mu-1}\),\(-\sqrt{\mu-1}\). Bifurcations occur at these points. Different behaviors observed in each system depend on the values of \(\mu\).

Step by step solution

01

Equilibrium Points for Equation a.

To find the equilibrium points, set the function equal to zero. Solve for y in the equation \(y^{\prime}=y-\mu y^{2}=0\). Doing this yields \(y=0\) and \(y= \mu\).
02

Bifurcation Points and Diagram for Equation a.

The system undergoes a bifurcation at \(y=0\) and \(y=\mu\). This is because these are the points where the stability of the system changes. Plot these points on a diagram with \(y\) on the y-axis and \(\mu\) on the x-axis.
03

Equilibrium Points for Equation b.

Solving the equation \(y^{\prime}=y(\mu-y)(\mu-2 y)=0\), gives three equilibrium points, \(y=0\), \(y=\mu\), and \(y=\mu/2\).
04

Bifurcation Points and Diagram for Equation b.

The system undergoes a bifurcation at \(y=0\), \(y=\mu\) and \(y=\mu/2\). Plot these points on a diagram with \(y\) on the y-axis and \(\mu\) on the x-axis.
05

Equilibrium Points for Equation c.

Solving the equation \(x^{\prime}=\mu-x^{3}=0\), we get the equilibrium points \(x=\sqrt[3]{\mu}\), \(x=-\sqrt[3]{\mu/2}\), and \(x= \sqrt[3]{\mu/2}\).
06

Bifurcation Points and Diagram for Equation c.

The system undergoes a bifurcation at \(x=\sqrt[3]{\mu}\), \(x=-\sqrt[3]{\mu/2}\), and \(x= \sqrt[3]{\mu/2}\). Plot these points on a diagram with \(x\) on the y-axis and \(\mu\) on the x-axis.
07

Equilibrium Points for Equation d.

Solving \(x^{\prime}=x-\frac{\mu x}{1+x^{2}}=0\) gives equilibrium points \(x=0\) and \(x=\sqrt{\mu-1}\),\(-\sqrt{\mu-1}\).
08

Bifurcation Points and Diagram for Equation d.

The system undergoes a bifurcation at \(x=0\), \(x=\sqrt{\mu-1}\), and \(x=-\sqrt{\mu-1}\). Plot these points on a diagram with \(x\) on the y-axis and \(\mu\) on the x-axis.
09

Discussion of system behavior

Each of the four system behaviors depends on the values of \(\mu\). For all, changes in stability occur at the bifurcation points which can be depicted in each bifurcation diagram. In the case of equations a and b, as \(\mu\) increases, the stable point transitions from one equilibrium point to another. For equations c and d, the systems show more complex bifurcations involving increases and decreases in stability at different equilibrium points.

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Most popular questions from this chapter

8\. Find the fixed points of the following systems. Linearize the system about each fixed point and determine the nature and stability in the neighborhood of each fixed point, when possible. Verify your findings by plotting phase portraits using a computer. a. $$ \begin{aligned} &x^{\prime}=x(100-x-2 y) \\ &y^{\prime}=y(150-x-6 y) \end{aligned} $$ b. $$ \begin{aligned} x^{\prime} &=x+x^{3} \\ y^{\prime} &=y+y^{3} \end{aligned} $$ C. $$ \begin{aligned} &x^{\prime}=x-x^{2}+x y \\ &y^{\prime}=2 y-x y-6 y^{2} \end{aligned} $$ d. $$ \begin{aligned} &x^{\prime}=-2 x y \\ &y^{\prime}=-x+y+x y-y^{3} \end{aligned} $$.

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