Find the Fourier transform, \(\hat{f}(k)\), of \(f(x)=e^{-2 x^{2}+x}\).

Short Answer

Expert verified
The Fourier transform, \( \hat{f}(k) \), of the function \(f(x)=e^{-2 x^{2}+x}\) is given by \(\hat{f}(k) = e^{\pi^2 k^2 - \frac{1}{16}}\sqrt{\pi}\)

Step by step solution

01

Identify the function

Identify the function which is to be transformed which in this case is \(f(x)=e^{-2 x^{2}+x}\).
02

Recall the formula for Fourier Transform

The formula for the Fourier Transform is \(\hat{f}(k) = \int_{-\infty}^{\infty} f(x) e^{-2 \pi i k x} dx\). Here, \( \hat{f}(k) \) represents the Fourier transform of \( f(x) \), and \( k \) is the frequency variable.
03

Substitute the function into the Fourier Transform formula

Now, substitute \( f(x) = e^{-2 x^{2}+x} \) in the Fourier transform formula. It gives \(\hat{f}(k) = \int_{-\infty}^{\infty} e^{-2 x^{2}+x} e^{-2 \pi i k x} dx\). This creates a manageable integral.
04

Consolidate the exponentials

Combine the terms \(-2x^{2} + x\) and \(-2\pi ikx\) under one exponential to get an equation in the form of a quadratic identity which can be later simplified for the integral. It gives \(\hat{f}(k) = \int_{-\infty}^{\infty} e^{-2 x^{2}+(1-2\pi ik)x} dx\).
05

Identify the quadratic form

To integrate this exponential, it is ideal to identify a perfect square. This can be factored into \((x-\pi ik)^{2}\). After solving, the integrand matches the formula of integral of a Gaussian, \(\int_{-\infty}^{\infty} e^{-x^{2}} dx = \sqrt{\pi}\) and the Fourier Transform is calculated.
06

Final evaluation of Fourier Transform

After evaluating and simplifying, we get the Fourier Transform. \(\hat{f}(k) = e^{\pi^2 k^2 - \frac{1}{16}}\sqrt{\pi}\)

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