Show that the Lie derivative \(\mathcal{L}_{x}\) commules with all operations of contraction \(C_{t}^{y}\) on a tensor field \(T\), $$ \mathcal{L}_{X} C_{J} T=C_{j} \mathcal{L}_{\mathrm{Y}} T $$

Short Answer

Expert verified
Therefore, it's proven that the Lie derivative \(\mathcal{L}\) commutes with all operations of contraction \(C_{J}\) on a tensor field \(T\).

Step by step solution

01

Definition of the Lie derivative

The Lie derivative \(\mathcal{L}_X\) of a tensor field T in direction X is given by the limit: \[ \mathcal{L}_XT = \lim_{t→0} \frac{\phi_t^*T - T}{t} \] Where \(\phi_t\) is the flow of X
02

Apply contraction to both sides of the Lie derivative definition

Now apply contraction \(C_J\) to both sides of this definition to get: \[ C_J(\mathcal{L}_XT) = \lim_{t→0} \frac{C_J(\phi_t^*T - T)}{t} \]
03

Applying the Leibnitz rule

Now, we can apply the Leibnitz rule (which states that contraction operations distribute over addition and scale with scalar multiplication) on the right hand side of this equation: \[ C_J(\mathcal{L}_XT) = \lim_{t→0} \frac{C_J(\phi_t^*T)-C_J(T)}{t} \]
04

Recognizing the Lie derivative

Now one can observe that the right hand side is just the definition of the Lie derivative applied to contraction of the tensor field \(T\), hence: \[ C_J(\mathcal{L}_XT) = \mathcal{L}_X(C_JT) \]

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