Chapter 1: Problem 10
\(\sum_{n=1}^{\infty} \frac{(-1)^{n} x^{2 n}}{(2 n)^{3 / 2}}\)
Short Answer
Expert verified
The series \(\frac{(-1)^n x^{2n}}{(2n)^{3/2}}\) converges by the Alternating Series Test.
Step by step solution
01
- Recognize the Series
The given series is \(\frac{(-1)^n x^{2n}}{(2n)^{3/2}}\) from \(n = 1\) to \(\text{infinity}\). This is an alternating series.
02
- Identify the General Term
The general term of the series is \(\frac{(-1)^n x^{2n}}{(2n)^{3/2}}\).
03
- Check for Convergence
Since this is an alternating series, use the Alternating Series Test (Leibniz test). Check two conditions: \(1\) The absolute value of the terms \(a_n = \frac{x^{2n}}{(2n)^{3/2}}\) decreases, and \(2\) \(a_n \rightarrow 0\) as \(n \rightarrow \text{infinity} \).
04
- Ensure Decreasing Terms
To confirm the series terms decrease, observe \(a_n = \frac{x^{2n}}{(2n)^{3/2}}\). As n increases, \( (2n)^{3/2} \) increases faster than \( x^{2n} \), ensuring the terms decrease.
05
- Evaluate the Limit
Evaluate \(\frac{x^{2n}}{(2n)^{3/2}} \rightarrow 0 \) as \ n \rightarrow \text{infinity}\. Since \(x^{2n}\rightarrow 0\) faster than \((2n)^{3/2}\) grows, the term approaches 0.
06
- Determine Convergence
Both conditions of the Alternating Series Test are met. Therefore, the series \(\frac{(-1)^n x^{2n}}{(2n)^{3/2}}\) converges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
series convergence
Series convergence is when the sum of the terms in an infinite series approaches a fixed number as more terms are added. In maths, we check if adding up all terms in a series will result in a finite value. It’s like having an endless list of numbers, but when you add them all up, they don’t just keep getting bigger without bound.
For a series to converge, it must meet certain criteria. One common method is the nth-term test, where if the limit of the nth term as n approaches infinity is not zero, the series diverges. But if it is zero, we need further tests.
In the exercise, the series \(\frac{(-1)^n x^{2n}}{(2n)^{3/2}}\) converges. Both steps in the test are satisfied, meaning its sum approaches a fixed value.
For a series to converge, it must meet certain criteria. One common method is the nth-term test, where if the limit of the nth term as n approaches infinity is not zero, the series diverges. But if it is zero, we need further tests.
In the exercise, the series \(\frac{(-1)^n x^{2n}}{(2n)^{3/2}}\) converges. Both steps in the test are satisfied, meaning its sum approaches a fixed value.
Leibniz test
The Leibniz test, also known as the Alternating Series Test, is a method to determine the convergence of alternating series. An alternating series is a series where the terms alternate in sign, like positive, negative, positive, negative, etc. The test states that an alternating series \(\sum (-1)^n b_n\) converges if two conditions are met:
The alternating series in our exercise, \(\frac{(-1)^n x^{2n}}{(2n)^{3/2}}\), meets these conditions, confirming its convergence.
- The absolute value of the terms \((b_n)\) decreases monotonically, i.e., each term is smaller than the previous term in absolute value.
- The limit of the terms \((b_n)\) as n approaches infinity is 0.
The alternating series in our exercise, \(\frac{(-1)^n x^{2n}}{(2n)^{3/2}}\), meets these conditions, confirming its convergence.
alternating series test
The Alternating Series Test helps in analyzing series where the sign alternates between terms. It’s another name for the Leibniz test and is very useful. It particularly focuses on alternating series.
The test checks two critical conditions:
In the given exercise, we distinguished the series \(\frac{(-1)^n x^{2n}}{(2n)^{3/2}}\) and verified both key points. Terms decrease, and the limit converges to zero.
The test checks two critical conditions:
- The series terms decrease in absolute value, termed as being monotonically decreasing. This ensures no term in absolute value is larger than the one before it.
- The limit of the terms \((a_n)\) as n approaches infinity equals zero. Without this, the terms wouldn't collectively settle to a finite sum.
In the given exercise, we distinguished the series \(\frac{(-1)^n x^{2n}}{(2n)^{3/2}}\) and verified both key points. Terms decrease, and the limit converges to zero.
mathematical sequences
A sequence is an ordered list of numbers or terms. Each number in the list is called a term. Sequences can be finite or infinite, and they often follow a specific rule or pattern.
In mathematical analysis, sequences are important because they form the backbone of series. If you sum up the terms of a sequence, you get a series. For example, the sequence in the exercise is \(\frac{x^{2n}}{(2n)^{3/2}}\). Each term follows this precise formula.
Understanding sequences helps us analyze their behavior as the index n increases to infinity. In convergence tests, we often examine how the terms of these sequences behave to determine if the series will reach a finite sum.
In mathematical analysis, sequences are important because they form the backbone of series. If you sum up the terms of a sequence, you get a series. For example, the sequence in the exercise is \(\frac{x^{2n}}{(2n)^{3/2}}\). Each term follows this precise formula.
Understanding sequences helps us analyze their behavior as the index n increases to infinity. In convergence tests, we often examine how the terms of these sequences behave to determine if the series will reach a finite sum.