Find the eigenvalues and eigenvectors of the following matrices.\(\left(\begin{array}{rrr}-1 & 1 & 3 \\ 1 & 2 & 0 \\ 3 & 0 & 2\end{array}\right)\)

Short Answer

Expert verified
The eigenvalues and their associated eigenvectors are determined by solving the characteristic polynomial and equation \( (A - \lambda I) \mathbf{v} = 0 \).

Step by step solution

01

Define the Characteristic Equation

To find the eigenvalues of the matrix, start by finding the characteristic polynomial. The characteristic equation is given by \(\text{det}(A - \text{I} \lambda) = 0\), where \(A\) is the matrix and \(\lambda\) is the eigenvalue.
02

Compute the Determinant

Subtract \(\lambda\) multiplied by the identity matrix from matrix \(A\). \[ A - I \lambda = \left(\begin{array}{rrr}-1 - \lambda & 1 & 3 \ 1 & 2 - \lambda & 0 \ 3 & 0 & 2 - \lambda \end{array}\right)\]. Next, calculate the determinant of this matrix.
03

Solve the Determinant

Calculate the determinant of the matrix \(A - I \lambda\): \[( -1 - \lambda)((2 - \lambda)(2 - \lambda) - 0) - 1(1 \cdot 2 - \lambda \cdot 0) + 3(1 \cdot 0 - 3 \cdot 1) = 0\].
04

Simplify the Polynomial

Simplify the expression to get the characteristic polynomial: \[(-1 - \lambda)((2 - \lambda)(2 - \lambda)) - 9 = 0\], which simplifies to: \[(-1 - \lambda)(\lambda^2 - 4\lambda) - 9 = 0.\]
05

Solve for the Eigenvalues

Expand the simplified polynomial to solve for \(\lambda\): \[(-1)(\lambda^3 - 4\lambda^2) + \lambda(\lambda^2 - 4\lambda) - 9 = 0.\] Solve the polynomial equation to find the eigenvalues.
06

Find the Eigenvectors

For each eigenvalue \(\lambda \), find the associated eigenvector \( \mathbf{v} \) by solving the equation \(( A - I \lambda) \mathbf{v} = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Characteristic Polynomial
To find the eigenvalues of a matrix, we need to calculate the characteristic polynomial. This polynomial is derived from the characteristic equation: \( \text{det}(A - I\text{ } \lambda) = 0\). Here, \(A\) is the matrix, \(\text{I}\) is the identity matrix, and \(\text{det}\) stands for the determinant. The eigenvalues \(\lambda\) are the roots of this polynomial.
Determinant
The determinant is a special number derived from a square matrix. To find the eigenvalues, you subtract \( \lambda\) times the identity matrix from \(A\), and then calculate the determinant of this new matrix. For our given matrix, we perform: \[ \left(\begin{array}{rrr}-1 - \lambda & 1 & 3 \ 1 & 2 - \lambda & 0 \ 3 & 0 & 2 - \lambda\end{array}\right) \]. This process is essential in finding eigenvalues because the determinant being zero is the key condition given by the characteristic equation.
Eigenvalue Equation
The eigenvalue equation is formed from the characteristic polynomial. After computing the determinant, we simplify the resulting polynomial to find the eigenvalues. This typically involves algebraic manipulation to solve for \(\lambda\). For example, after going through the steps of simplification, you might get an equation like \( (-1 - \lambda)(\lambda^2 - 4\lambda) - 9 = 0\), which you then solve for the roots to find the eigenvalues.
Matrix Algebra
Matrix algebra involves various operations with matrices, such as addition, subtraction, and multiplication. It also includes more complex operations like finding the determinant and the inverse of a matrix. In the context of eigenvalues and eigenvectors, matrix algebra skills are crucial. You need to be comfortable manipulating matrices to subtract \(\lambda \text{I}\) from \(A\) and to solve the resultant matrix equations.
Linear Transformations
Linear transformations are functions that map vectors to other vectors, preserving the operations of vector addition and scalar multiplication. Matrices can represent these transformations. An eigenvalue \(\lambda\) of a transformation \(A\) is a scalar such that for a certain non-zero vector \( \mathbf{v}\), the transformation scales \( \mathbf{v}\) by \ \lambda \. In simpler terms, \( A \mathbf{v} = \lambda \mathbf{v}\). Finding eigenvalues and eigenvectors means identifying these scalings and the associated vectors for the transformation described by the matrix \(A\).

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Most popular questions from this chapter

Let each of the following matrices \(M\) describe a deformation of the \((x, y)\) plane. For each given \(M\) find: the eigenvalues and eigenvectors of the transformation, the matrix \(C\) which diagonalizes \(M\) and specifies the rotation to new axes \(\left(x^{\prime}, y^{\prime}\right)\) along the eigenvectors, and the matrix \(D\) which gives the deformation relative to the new axes. Describe the deformation relative to the new axes.\(\left(\begin{array}{ll}3 & 1 \\ 1 & 3\end{array}\right)\)

(a) Show that the product of two symmetric matrices is symmetric if and only if they commute. (b) When is the product of two Hermitian matrices a Hermitian matrix?

Let \(\mathbf{T}\) be a second-order tensor (dyadic) and let \(\mathrm{V}\) be a vector. Then we have seen that \(\mathbf{T} \cdot \mathrm{V}\) is another vector, say U. Write the equations giving each of the three components of \(\mathrm{U}\) as linear combinations of the three components of \(\mathrm{V} ;\) write these equations in matrix form, dyadic form, and summation form. Observe that the nine coefficients in these linear combinations are just the nine components of \(T\).

Given \(\mathbf{V}=2 \mathbf{i}-3 \mathrm{j}, \mathbf{U}=\mathbf{i}+2 \mathbf{k}\), write the dyadics \(\mathbf{U} \mathbf{V}\) and \(\mathbf{V U}\) in dyadic and in matrix form. Find \(\mathbf{W}=(\mathrm{UV}) \cdot \mathbf{U}\) and write this equation in matrix form.

The trace of a matrix is the sum of the elements on the main diagonal. Show that the trace is not changed by cyclic permutation of the matrices, that is, \(\operatorname{Tr}(A B C)=\operatorname{Tr}(C A B)=\) Tr \((B C A)\). [Caution: \(\operatorname{Tr}(A B C) \neq \operatorname{Tr}(A C B)\) in general. ]

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