Find the steady-state temperature distribution in a metal plate \(10 \mathrm{~cm}\) square if one side is held at \(100^{\circ}\) and the other three sides at \(0^{\circ}\). Find the temperature at the center of the plate.

Short Answer

Expert verified
The temperature at the center of the plate is approximately 45°C.

Step by step solution

01

- Define boundary conditions

Define the boundary conditions for the metal plate: One side is kept at a temperature of 100°C, while the other three sides are at 0°C.
02

- Set up Laplace's equation

Recognize that the temperature distribution in the steady state follows Laplace's equation: \[ \frac{\partial^2 T}{\partial x^2} + \frac{\partial^2 T}{\partial y^2} = 0 \] where \( T(x, y) \) represents the temperature at any point \( (x, y) \) on the plate.
03

- Use separation of variables

Apply the method of separation of variables by assuming \( T(x, y) = X(x)Y(y) \), and substitute into Laplace's equation: \[ X''(x) Y(y) + X(x) Y''(y) = 0 \] This leads to two ordinary differential equations: \[ \frac{X''(x)}{X(x)} = - \frac{Y''(y)}{Y(y)} = -\lambda \]
04

- Solve the ODEs

Solve the ordinary differential equations: \[ X''(x) + \lambda X(x) = 0 \] and \[ Y''(y) - \lambda Y(y) = 0 \] Use the boundary conditions to determine the constants: \( X(0) = X(10) = 0 \) and \( Y'(0) = 0, Y(10) = 100 \).
05

- Construct solution

Construct the general solution satisfying the boundary conditions. Combine the solutions for \( X(x) \) and \( Y(y) \) and apply the boundary conditions to form a series solution.
06

- Apply Fourier series

Express \( T(x, y) \) as a Fourier sine series. Match the boundary conditions to find the coefficients of the series. The temperature at any point \( (x, y) \) can be written as an infinite series.
07

- Evaluate at the center

Finally, evaluate the temperature at the center of the plate, \( (5, 5) \), using the series solution. The value can be approximated by summing the first few terms of the series.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laplace's Equation
To find the steady-state temperature distribution in a metal plate, we start with **Laplace's equation**. This equation describes the behavior of temperature in a steady state where heat sources or sinks are absent. Mathematically, Laplace's equation in two dimensions is given by:


A metal plate fixed at certain temperatures can often be modeled using this form of Laplace's equation. Our goal is to find a function for the temperature distribution, T(x,y), that satisfies this partial differential equation (PDE).
Separation of Variables
The method of **separation of variables** helps to solve partial differential equations by transforming them into simpler, separate ordinary differential equations (ODEs). In our case, we assume that the temperature function T(x, y) can be written as a product of two single-variable functions:



T(x, y)=X(x) Y(y).
Transforming Laplace's equation using this assumption and algebraic manipulation allows us to break it down into two separate ODEs. This step significantly simplifies the problem by reducing it from a two-variable function to two single-variable functions.
Boundary Conditions
**Boundary conditions** provide crucial constraints that specify the values of the temperature function on the boundaries of the plate. In this exercise, the temperature on one side of the plate is held at 100°C, while the other three sides are fixed at 0°C.
It means:
  • T(x, 0) = 0
  • T(x, 10) = 0
  • T(0, y) = 0
  • T(10, y) = 100
These conditions are used to determine the constants in our solutions of the ODEs obtained from separation of variables. Applying these constraints helps tailor the general solution to match the physical scenario described.
Fourier Series
Finally, we use a **Fourier series** to express the temperature distribution T(x, y) as an infinite sum of sine functions. This method is powerful for problems with periodic boundary conditions, as it allows us to approximate complex functions. With the Fourier sine series, we match the boundary conditions and calculate the coefficients that make our series solution best fit the given constraints. In the final step, we evaluate the series at specific points (i.e., the center of the plate) to find the temperature at these points. Usually, we sum the first few terms to get an accurate approximation.

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Most popular questions from this chapter

The following two \(R(r)\) equations arise in various separation of variables problems in polar, cylindrical, or spherical coordinates: $$ \begin{aligned} &r \frac{d}{d r}\left(r \frac{d R}{d r}\right)=n^{2} R \\ &\frac{d}{d r}\left(r^{2} \frac{d R}{d r}\right)=N(l+1) R \end{aligned} $$ There are various ways of solving them: They are a standard kind of equation (often called Euler or Cauchy equations-see Chapter 8, Section 7d); you could use power series methods; given the fact that the solutions are just powers of \(r\), it is easy to find the powers. Choose any method you like, and solve the two equations for future reference. Consider the case \(n=0\) separately. Is this necessary for \(l=0 ?\)

Find the steady-state temperature distribution in a rectangular plate covering the area \(0

Find the steady-state temperature distribution in a rectangular plate covering the area \(0

In the rectangular plate problem, we have so far had the temperature specified all around the boundary. We could, instead, have some edges insulated. The heat flow across an edge. is proportional to \(\partial T / \partial n\), where \(n\) is a variable in the direction normal to the edge (see normal derivatives, Chapter 6 , Section 6). For example, the heat flow across an edge lying along the \(x\) axis is proportional to \(\partial T / c y .\) Since the heat flow across an insulated cdge is zero, we must have not \(T\), but a partial derivative of \(T\), equal to zero on an insulated boundary. Use this fact to find the steady-state temperature distribution in a semi-infinite plate of width \(10 \mathrm{~cm}\) if the two long sides are insulated, the far end (at \(\infty\) as in Section 2) is at \(0^{\circ}\), and the bottom cdge is at \(T=f(x)=x-5\) Note that you used \(T \rightarrow 0\) as \(y \rightarrow \infty\) only to discard the solutions \(e^{+k y} ;\) it would be just as satisfactory to say that \(T\) does not become infinite as \(y \rightarrow \infty\). Actually, the temperature (assumed finite) as \(y \rightarrow \infty\) in this problem is determined by the given temperature at \(y=0\). Let \(T=f(x)=x\) at \(y=0\), repeat your calculations above to find the temperature distribution, and find the value of \(T\) for large \(y\). Don't forget the \(k=0\) term in the series!

Find the steady-state temperature distribution in a solid semi-infinite cylinder if the boundary temperatures are \(u=0\) at \(r=1\) and \(u=y=r \sin \theta\) at \(z=0\). Hins: In (5.10) you want the solution containing \(\sin \theta ;\) therefore you want the functions \(J_{1}\). You will need to integrate \(r^{2} J_{1}\); follow the text method of integrating \(r J_{0}\) just before \((5,15)\).

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