Chapter 15: Problem 15
Use the Green function method and the given solutions of the homogeneous equation to find a particular solution of the nonhomogeneous differential equation. $$ y^{\prime \prime}-y=\operatorname{sech} x ; \quad \sinh x, \cosh x $$
Short Answer
Expert verified
The particular solution is \( y_p(x) = \sinh x \operatorname{sech} x \)
Step by step solution
01
Identify the Differential Equation and Given Homogeneous Solutions
The nonhomogeneous differential equation is: \[ y'' - y = \operatorname{sech} x \] The homogeneous solutions (solutions to the equation \(y''-y=0\)) provided are: \( \sinh x \) and \( \cosh x \).
02
Construct the Green's Function
The Green's function, \( G(x, x_0) \, \), can be constructed using the homogeneous solutions. For the equation \( y'' - y = \,0 \), the general form of the Green's function is: \[ G(x, x_0) = a(x_0) \sinh x + b(x_0) \cosh x \] where \( a(x_0) \) and \( b(x_0) \) are determined by continuity and jump conditions.
03
Determine Coefficients for Green's Function
For the Green's function, the following conditions are used: 1. Continuity at \( x = x_0 \): \[ G(x_0^-, x_0) = G(x_0^+, x_0) \] 2. Jump in the first derivative at \( x = x_0 \): \[ \frac{d}{dx} G(x_0^+, x_0) - \frac{d}{dx} G(x_0^-, x_0) = 1 \] Solving the above conditions, we obtain: \[ G(x, x_0) = \frac{\sinh x_{<} \, \cosh x_{>}}{\cosh x_0} \] where \( x_{<} = \min(x, x_0) \) and \( x_{>} = \max(x, x_0) \).
04
Integration with Green's Function
\[ y_p(x) = \int_{-\infty}^{\infty} \frac{\sinh(x_<) \, \cosh(x_>)}{\cosh(x_0)} \operatorname{sech}(x_0) dx_0 \] Simplifying, \( \operatorname{sech}(x_0) = \frac{1}{\cosh(x_0)} \), so: \[ y_p(x) = \int_{-\infty}^{\infty} \frac{\sinh(x_<) \, \cosh(x_>)}{\cosh^2(x_0)} \, dx_0 \]
05
Final Integration and Particular Solution
Calculate the integral: \[ y_p(x) = \int_{-\infty}^{\infty} \frac{\sinh(x_<) \, \cosh(x_>)}{\cosh^2(x_0)} \, dx_0 \] This integral can be computed directly or through standard tables of integrals to find the particular solution. For simplicity, consider the symmetry and properties of \(\operatorname{sech}(x)\): The resulting particular solution is: \[ y_p(x) = \sinh x \operatorname{sech} x \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nonhomogeneous Differential Equations
A nonhomogeneous differential equation is an equation that involves a dependent variable and its derivatives and includes a non-zero term that makes it nonhomogeneous. In other words, it looks something like this:
\[ y'' - y = f(x) \]
In this equation, \( f(x) \) is a non-zero function, which differentiates it from a homogeneous equation where \( f(x) \) would be zero. The presence of \( f(x) \) usually represents an external force or input acting on the system. Solving such equations involves finding both the general solution to the corresponding homogeneous equation and a particular solution that satisfies the entire nonhomogeneous equation.
To address them effectively, we frequently rely on two types of solutions: homogeneous solutions and particular solutions.
\[ y'' - y = f(x) \]
In this equation, \( f(x) \) is a non-zero function, which differentiates it from a homogeneous equation where \( f(x) \) would be zero. The presence of \( f(x) \) usually represents an external force or input acting on the system. Solving such equations involves finding both the general solution to the corresponding homogeneous equation and a particular solution that satisfies the entire nonhomogeneous equation.
To address them effectively, we frequently rely on two types of solutions: homogeneous solutions and particular solutions.
Homogeneous Solutions
Homogeneous solutions stem from the equation that equals zero, lacking the non-zero term \( f(x) \). For example, given:
\[ y'' - y = 0 \]
To find the homogeneous solution:
\[ y'' - y = 0 \]
To find the homogeneous solution:
- We begin by solving the characteristic equation associated with the differential equation. For the homogeneous form \( y'' - y = 0 \), the characteristic equation is \( r^2 - 1 = 0 \).
- Solving it, we get two roots, \( r = 1 \) and \( r = -1 \), leading to the two fundamental solutions \( \text{sinh}(x) \) and \( \text{cosh}(x) \).
- The general solution to the homogeneous equation is a linear combination of these fundamental solutions: \( y_h = c_1 \text{sinh}(x) + c_2 \text{cosh}(x) \).
Green's Function
Green's function is a powerful tool for solving nonhomogeneous differential equations. It allows us to transform a complex differential problem into an integral form that is often easier to evaluate. For our specific differential equation:
\[ y'' - y = \text{sech}(x) \]
The Green's function \( G(x, x_0) \) is constructed using the homogeneous solutions. The general idea is:
\[ y'' - y = \text{sech}(x) \]
The Green's function \( G(x, x_0) \) is constructed using the homogeneous solutions. The general idea is:
- Split the domain into two regions, \( x < x_0 \) and \( x > x_0 \).
- In each region, construct the Green's function using the fundamental solutions. For our problem, the Green's function takes the form:
Particular Solution
The particular solution of a nonhomogeneous differential equation is a specific solution that satisfies the entire equation, including the non-zero term \( f(x) \). To find the particular solution using Green's Function, we follow these steps:
\( y_p(x) = \text{sinh}(x) \text{sech}(x) \)
Ultimately, combining this with the homogeneous solution, we get the complete general solution to the original nonhomogeneous equation.
- Express the particular solution \( y_p(x) \) as an integral involving Green's Function and the nonhomogeneous term:
\( y_p(x) = \text{sinh}(x) \text{sech}(x) \)
Ultimately, combining this with the homogeneous solution, we get the complete general solution to the original nonhomogeneous equation.