Chapter 15: Problem 38
Evaluate each of the following definite integrals by using the Laplace transform table. $$ \int_{0}^{\pi} e^{-t}(1-\cos 2 t) d t $$
Short Answer
Expert verified
Laplace integrals involve seeing boundaries with transforms and evaluating initial expressions.
Step by step solution
01
Identify the Laplace Transform
Recognize the integral's form and look for the Laplace transforms of the components in the integral. Here we need the transforms for \(e^{-t}\) and \(e^{-t}\text{cos}(2t)\).
02
Find the Laplace Transform of Individual Functions
Consult a Laplace transform table. We find that:1. \( \text{Laplace}(e^{-t}) = \frac{1}{s+1} \)2. \( \text{Laplace}(e^{-t}\text{cos}(2t)) = \frac{s+1}{(s+1)^2 + 4} \)
03
Linearity Property of the Laplace Transform
Use the linearity property of the Laplace transform, which states that:\( \text{Laplace}(af(t) + bg(t)) = a \text{Laplace}(f(t)) + b \text{Laplace}(g(t)) \)Here, the integral becomes a combination of the transforms found.
04
Apply the Bounds to Find the Integral
Evaluate the transform from 0 to \( \frac{\pi}{s+1} \ \):\(\int_0^{\pi} e^{-t}(1-\text{cos}(2t)) dt = \text{Laplace}^{-1}\bigg(\frac{1}{s+1}\bigg|_0^{\pi} - \frac{s+1}{(s+1)^2 + 4}\bigg|_0^{\pi}\bigg) \)
05
Evaluate Inverse Transforms
Use the inverse transform at the bounds and subtract the lower limit from the upper limit values. Simplify results as much as needed.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
definite integrals
Definite integrals are a fundamental concept in calculus. They represent the area under the curve of a function between two specified bounds, say from \( a \) to \( b \). In our context, we are evaluating the definite integral \[ \int_{0}^{\pi} e^{-t}(1 - \cos(2t)) dt \]. This specific type of integral can often be tackled using advanced techniques like Laplace transforms, especially when dealing with complex exponentials and trigonometric functions. When handling definite integrals, remember:
- The integral calculates the net area between the curve and the x-axis over the interval.
- Integrals can represent a wide variety of physical quantities such as distance, area, volume, and more.
Laplace transform table
The Laplace transform table is an invaluable tool for quickly identifying the Laplace transforms of common functions. To solve the integral, we used the transform table to find the transforms of \( e^{-t} \) and \( e^{-t} \cos(2t) \). The pertinent transforms are:
- \( \text{Laplace}(e^{-t}) = \frac{1}{s+1} \)
- \( \text{Laplace}(e^{-t} \cos(2t)) = \frac{s+1}{(s+1)^2 + 4} \)
linearity property of Laplace transforms
The linearity property of Laplace transforms is a powerful attribute. It states that the Laplace transform of a linear combination of functions is the same combination of their individual transforms. Mathematically:
- \( \text{Laplace}(af(t) + bg(t)) = a \text{Laplace}(f(t)) + b \text{Laplace}(g(t)) \)
inverse Laplace transforms
To return to the time domain after using Laplace transforms, we use the concept of the inverse Laplace transform. This process transforms the function back from the s-domain to the time domain. In our example, after transforming each component, we apply the bounds and then take the inverse Laplace transform to solve the original definite integral. The steps are:
- Apply the transforms and combine based on the integral's formula.
- Evaluate within the given bounds from \( t = 0 \) to \( t = \pi \).
- Perform the inverse Laplace transform to interpret the solution in the original domain.