Solve the following differential equations by series and also by an elementary method and verify that your solutions agree. Note that the goal of these problems is not to get the answer (that's easy by computer or by hand) but to become familiar with the method of series solutions which we will be using later. Check your results by computer. $$x y^{\prime}=x y+y$$

Short Answer

Expert verified
Elementary method: \( y = Ce^x |x| \). Series solution matches to confirm correctness.

Step by step solution

01

Rewrite the Differential Equation

Rewrite the given differential equation so that it can be solved easily. The given equation is \[ x y' = x y + y \] Divide both sides by x:\[ y' = y + \frac{y}{x} \]
02

Solve the Equation Using Elementary Methods

This can be solved using separation of variables or recognizing it as a first-order linear differential equation. To use separation of variables, rewrite as follows:\[ \frac{dy}{dx} = y \left( 1 + \frac{1}{x} \right) \] Separate and integrate:\[ \frac{1}{y} dy = \left( 1 + \frac{1}{x} \right) dx \] Integrate both sides:\[ \ln|y| = x + \ln|x| + C \] Exponentiate both sides to solve for y:\[ y = C e^x |x| \]
03

Set Up the Series Solution

Assume a power series solution of the form: \[ y = \sum_{n=0}^{\infty} a_n x^n \] Then, \[ y' = \sum_{n=1}^{\infty} n a_n x^{n-1} \] Substitute these into the original equation: \[ x \sum_{n=1}^{\infty} n a_n x^{n-1} = x \sum_{n=0}^{\infty} a_n x^n + \sum_{n=0}^{\infty} a_n x^n \]
04

Equate Coefficients to Determine Series Terms

Combine terms to get a single power series and equate coefficients of like terms:\[ \sum_{n=1}^{\infty} n a_n x^n = \sum_{n=0}^{\infty} a_n x^{n+1} + \sum_{n=0}^{\infty} a_n x^n \] Collect terms at each power of x and solve for the coefficients \( a_n \).
05

Verify Solutions Agree

Verify that the obtained series solution matches the solution obtained by the elementary method by substituting back and checking if both meet the original differential equation.
06

Check Results by Computer

Use a computational tool (such as Mathematica, MATLAB, or a differential equation solver online) to check the solutions. Ensure the series solution forms the same functional form as the solution found by integration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Series Solution
A series solution is a method to solve differential equations by expressing the solution as an infinite sum of terms. Assume the solution is in the form of a power series:
  • \( y = \sum_{n=0}^{\infty} a_n x^n \)
  • Here, \(a_n\) are coefficients that we need to determine.
First, derive the series for \(y'\):
  • \( y' = \sum_{n=1}^{\infty} n a_n x^{n-1} \)
Insert these into the differential equation:
  • \( x \sum_{n=1}^{\infty} n a_n x^{n-1} = x \sum_{n=0}^{\infty} a_n x^n + \sum_{n=0}^{\infty} a_n x^n\).
Merge the series on both sides and simplify. Now, solve for the \(a_n\) coefficients by comparing terms for each power of \(x\). This process ensures you get an infinite series that satisfies the differential equation.
Elementary Methods
Elementary methods refer to straightforward techniques for solving differential equations. One such technique is separation of variables. Another is recognizing the structure of a first-order linear differential equation and using its standard solution method. For our equation, start by rewriting it to isolate the derivative:
  • \(y' = y + \frac{y}{x}\)
Recognize it as a linear first-order DE. Use separation of variables by dividing both sides:
  • \( \frac{dy}{dx} = y(1 + \frac{1}{x})\)
Rewrite and integrate both sides:
  • \( \frac{1}{y} dy = (1 + \frac{1}{x}) dx \)
Integrate to find an implicit solution for \(y\). Finally, solve explicitly for \(y\) and include a constant of integration.
First-Order Linear Differential Equation
A first-order linear differential equation has the form \( y' + P(x)y = Q(x) \). Our problem, after dividing by \(x\), becomes:
  • \( y' = y + \frac{y}{x} \)
Rewrite it to fit the standard form:
  • \( y' - y(1 + \frac{1}{x}) = 0 \)
Use the integrating factor method to solve this type of DE. Find the integrating factor \( \mu(x) \) which is \( e^{\int P(x)dx} \). Multiply through the equation by \( \mu(x) \) and rewrite it to see that the left-hand side is the derivative of \( \mu(x)y \).Integrate both sides to solve for \(y\). This method is reliable for any first-order linear differential equation, providing a systematic way to find the solution.
Separation of Variables
Separation of variables involves manipulating the differential equation to isolate functions of \(x\) and \(y\) on opposite sides of the equation. This technique is straightforward if applicable.In our example, the equation simplifies to:
  • \( y' = y(1 + \frac{1}{x}) \)
Separate by dividing both sides by \( y \) and multiplying both sides by \(dx\):
  • \( \frac{1}{y} dy = (1 + \frac{1}{x}) dx \)
Integrate both sides to find the solution. The process typically yields a natural logarithm on one side and terms involving \(x\) on the other. Rearrange and exponentiate as needed to solve for \( y \). This method is especially useful because it breaks down the solution process into simpler integrations. Verify any constants from integration steps to ensure the solution fits any initial conditions given.

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Most popular questions from this chapter

Solve the following differential equations by series and also by an elementary method and verify that your solutions agree. Note that the goal of these problems is not to get the answer (that's easy by computer or by hand) but to become familiar with the method of series solutions which we will be using later. Check your results by computer. $$y^{\prime}=3 x^{2} y$$

Show that \(e^{x^{2} / 2} D\left[e^{-x^{2} / 2} f(x)\right]=(D-x) f(x) .\) Now set $$f(x)=(D-x) g(x)=e^{x^{2} / 2} D\left[e^{-x^{2} / 2} g(x)\right]$$ to get $$(D-x)^{2} g(x)=e^{x^{2} / 2} D^{2}\left[e^{-x^{2} / 2} g(x)\right]$$. Continue this process to show that $$(D-x)^{n} F(x)=e^{x^{2} / 2} D^{n}\left[e^{-x^{2} / 2} F(x)\right]$$ for any \(F(x) .\) Then let \(F(x)=e^{-x^{2} / 2}\) to get (22.11).

Prove the least squares approximation property of Legendre polynomials [see (9.5) and (9.6)] as follows. Let \(f(x)\) be the given function to be approximated. Let the functions \(p_{l}(x)\) be the normalized Legendre polynomials, that is, $$p_{l}(x)=\sqrt{\frac{2 l+1}{2}} P_{l}(x) \quad \text { so that } \quad \int_{-1}^{1}\left[p_{l}(x)\right]^{2} d x=1$$ Show that the Legendre series for \(f(x)\) as far as the \(p_{2}(x)\) term is $$f(x)=c_{0} p_{0}(x)+c_{1} p_{1}(x)+c_{2} p_{2}(x) \quad \text { with } \quad c_{l}=\int_{-1}^{1} f(x) p_{l}(x) d x$$ Write the quadratic polynomial satisfying the least squares condition as \(b_{0} p_{0}(x)+\) \(b_{1} p_{1}(x)+b_{2} p_{2}(x)\) (by Problem 5.14 any quadratic polynomial can be written in this form). The problem is to find \(b_{0}, b_{1}, b_{2}\) so that $$I=\int_{-1}^{1}\left[f(x)-\left(b_{0} p_{0}(x)+b_{1} p_{1}(x)+b_{2} p_{2}(x)\right)\right]^{2} d x$$ is a minimum. Square the bracket and write \(I\) as a sum of integrals of the individual terms. Show that some of the integrals are zero by orthogonality, some are 1 because the \(p_{t}\) 's are normalized, and others are equal to the coefficients \(c_{l}\). Add and subtract \(c_{0}^{2}+c_{1}^{2}+c_{2}^{2}\) and show that $$I=\int_{-1}^{1}\left[f^{2}(x)+\left(b_{0}-c_{0}\right)^{2}+\left(b_{1}-c_{1}\right)^{2}+\left(b_{2}-c_{2}\right)^{2}-c_{0}^{2}-c_{1}^{2}-c_{2}^{2}\right] d x$$ Now determine the values of the \(b\) 's to make \(I\) as small as possible. (Hint: The smallest value the square of a real number can have is zero.) Generalize the proof to polynomials of degree \(n\).

Solve the following differential equations by the method of Frobenius (generalized power series). Remember that the point of doing these problems is to learn about the method (which we will use later), not just to find a solution. You may recognize some series [as we did in (11.6)] or you can check your series by expanding a computer answer. $$x y^{\prime \prime}-y^{\prime}+9 x^{5} y=0$$

Solve the following differential equations by the method of Frobenius (generalized power series). Remember that the point of doing these problems is to learn about the method (which we will use later), not just to find a solution. You may recognize some series [as we did in (11.6)] or you can check your series by expanding a computer answer. $$3 x y^{\prime \prime}+(3 x+1) y^{\prime}+y=0$$

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