Recall that two events \(A\) and \(B\) are called independent if \(p(A B)=p(A) p(B) .\) Similarly two random variables \(x\) and \(y\) are called independent if the joint probability function \(f(x, y)=g(x) h(y) .\) Show that if \(x\) and \(y\) are independent, then the expectation or average of \(x y\) is \(E(x y)=E(x) E(y)=\mu_{x} \mu_{y}\).

Short Answer

Expert verified
If X and Y are independent, then \(E(XY) = E(X)E(Y) = \mu_x \mu_y\).

Step by step solution

01

Define Independence of Random Variables

Given two random variables, X and Y, they are independent if their joint probability function is the product of their individual probability functions: \(f(x, y) = g(x) h(y)\).
02

Define Expectation of a Function of Random Variables

The expectation of the product of X and Y is defined as \(E(XY)\). By definition, this means integrating the product \(x * y\) over the joint probability density function \(f(x, y)\):\[E(XY) = \int \int xy f(x, y) \, dx \, dy\]
03

Substitute Independence Condition

Given that X and Y are independent, substitute \(f(x, y) = g(x) h(y)\) into the expectation formula:\[E(XY) = \int \int xy g(x) h(y) \, dx \, dy\]
04

Separate the Integrals

Separate the double integral into the product of two single integrals: \[E(XY) = \int x g(x) \, dx \int y h(y) \, dy\]
05

Recognize Each Integral as an Expectation

Recognize that \(\int x g(x) \, dx\) is the definition of the expected value of X, \(E(X) = \mu_x\), and \(\int y h(y) \, dy\) is the expected value of Y, \(E(Y) = \mu_y\). Thus,\[E(XY) = E(X) \, E(Y) = \mu_x \mu_y\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Joint Probability Function
The concept of a joint probability function is essential when dealing with multiple random variables. Simply put, it's a function that gives us the probability that each of the variables falls within a specific range or takes on certain values simultaneously. For two random variables, X and Y, their joint probability function is denoted as \(f(x, y)\). If X and Y are independent, the joint probability function can be expressed as the product of their individual probability functions: \(f(x, y) = g(x) h(y)\). This means that the probability of X and Y occurring together is just the product of their separate probabilities. The joint probability function is crucial for understanding interactions between variables, particularly when determining their combined behavior.
Expectation of a Function
The expectation of a function of random variables provides us with the long-term average or mean value you would expect if an experiment were repeated many times. For example, the expectation of the product of X and Y, denoted as \(E(XY)\), is simply the average value of the product over all possible values of X and Y. Mathematically, this is expressed as \int \int xy f(x, y) \, dx \, dy\
.
This integral sums up the product \(xy\) weighted by their joint probabilities over the possible values of X and Y. For independent variables, substituting \(f(x, y) = g(x)h(y)\) allows breaking down the process into simpler, separate calculations for each variable.
Integration of Probability Density
The integration of a probability density function helps us find the expectation of a random variable or any function involving random variables. If you want to calculate the expectation of the product of independent random variables X and Y, you'd integrate their product over the joint density function:

\(E(XY) = \int \int xy f(x, y) \, dx \, dy\).

Substituting \(f(x, y) = g(x)h(y)\) since X and Y are independent, we get:

\(E(XY) = \int \int xy g(x)h(y) \, dx \, dy\).

The integration separates into:

\(E(XY) = ( \int x g(x) \, dx ) ( \int y h(y) \, dy )\).

Essentially, this breaks the problem into finding the expectations of X and Y separately and then multiplying these results. Integration in this context simplifies computing expectations for independent variables.
Expected Value
The expected value or expectation of a random variable is a fundamental concept in probability and statistics. It gives you a measure of the 'central' tendency or the mean value you'd anticipate over many trials. For any random variable X, its expected value, \(E(X)\), is computed as: \(E(X) = \int x g(x) \, dx\).

Similarly, for Y, the expected value is: \(E(Y) = \int y h(y) \, dy \).

If X and Y are independent random variables, the expected value of their product is simply the product of their individual expected values:

\(E(XY) = E(X)E(Y) = \mu_x \mu_y\).

This result is very useful when dealing with complex systems as it allows for simplifying calculations assuming independence of the involved variables. Understanding expected values is key to making predictions and informed decisions based on probabilistic models.

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Most popular questions from this chapter

(a) Three typed letters and their envelopes are piled on a desk. If someone puts the letters into the envelopes at random (one letter in each), what is the probability that each letter gets into its own envelope? Call the envelopes \(A, B, C,\) and the corresponding letters \(a, b, c,\) and set up the sample space. Note that " \(a\) in \(C\) \(b\) in \(B, c\) in \(A "\) is one point in the sample space. (b) What is the probability that at least one letter gets into its own envelope? Hint: What is the probability that no letter gets into its own envelope? (c) Let \(A\) mean that \(a\) got into envelope \(A\), and so on. Find the probability \(P(A)\) that \(a\) got into \(A\). Find \(P(B)\) and \(P(C)\). Find the probability \(P(A+B)\) that either \(a\) or \(b\) or both got into their correct envelopes, and the probability \(P(A B)\) that both got into their correct envelopes. Verify equation (3.6)

(a) There are 3 red and 5 black balls in one box and 6 red and 4 white balls in another. If you pick a box at random, and then pick a ball from it at random, what is the probability that it is red? Black? White? That it is either red or white? (b) Suppose the first ball selected is red and is not replaced before a second ball is drawn. What is the probability that the second ball is red also? (c) If both balls are red, what is the probability that they both came from the same box?

Suppose a coin is tossed three times. Let \(x\) be a random variable whose value is 1 if the number of heads is divisible by \(3,\) and 0 otherwise. Set up the sample space for \(x\) and the associated probabilities. Find \(\bar{x}\) and \(\sigma\).

Using both the binomial distribution and the normal approximation. Consider a biased coin with probability \(1 / 3\) of heads and \(2 / 3\) of tails and suppose it is tossed 450 times. (a) Find the probability of getting exactly 320 tails. (b) Find the probability of getting between 300 and 320 tails.

What is the probability that a number \(n, 1 \leq n \leq 99,\) is divisible by both 6 and \(10 ?\) By either 6 or 10 or both?

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