There are 3 red and 2 white balls in one box and 4 red and 5 white in the second box. You select a box at random and from it pick a ball at random. If the ball is red, what is the probability that it came from the second box?

Short Answer

Expert verified
The probability is approximately 0.460.

Step by step solution

01

- Understand the problem

Need to find the probability that a red ball came from the second box given that it was chosen at random.
02

- Define Events

Let A be the event that Box 1 is chosen, and B be the event that Box 2 is chosen. Let R be the event that a red ball is chosen.
03

- Determine Probabilities for Choosing Each Box

Since a box is chosen at random, the probability of choosing either box is equal: \[ P(A) = P(B) = \frac{1}{2} \]
04

- Determine Probabilities of Red Ball from Each Box

The probability of picking a red ball given that Box 1 was chosen is: \[ P(R|A) = \frac{3}{3+2} = \frac{3}{5} \] The probability of picking a red ball given that Box 2 was chosen is: \[ P(R|B) = \frac{4}{4+5} = \frac{4}{9} \]
05

- Use Bayes' Theorem

Using Bayes' Theorem, the probability that the red ball came from the second box is given by: \[ P(B|R) = \frac{P(R|B)P(B)}{P(R)} \]
06

- Find Total Probability of Red Ball

The total probability of drawing a red ball, P(R), is: \[ P(R) = P(R|A)P(A) + P(R|B)P(B) = \frac{3}{5} \times \frac{1}{2} + \frac{4}{9} \times \frac{1}{2} = \frac{3}{10} + \frac{4}{18} \approx 0.483 \]
07

- Calculate Final Probability

Substitute back into Bayes' Theorem: \[ P(B|R) = \frac{\frac{4}{9} \times \frac{1}{2}}{0.483} \approx 0.460 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bayes' Theorem
Bayes' Theorem is a powerful tool in probability theory that allows you to update the probability estimate for an event based on new evidence. Named after Thomas Bayes, it helps you find the probability of an event given that another event has occurred.
To understand Bayes' Theorem, it's essential to know the formula:
\[P(A|B) = \frac{P(B|A)P(A)}{P(B)}\]
Here's what each term means:
  • \(P(A|B)\) is the probability of event A occurring given that event B has occurred.
  • \(P(B|A)\) is the probability of event B occurring given that event A has occurred.
  • \(P(A)\) and \(P(B)\) are the probabilities of events A and B occurring independently of each other.
In our exercise, we want to determine the probability that a red ball came from the second box (event B) given that a red ball was picked (event R). Bayes' Theorem helps us update our initial beliefs based on this new information.
Probability Theory
Probability Theory is a branch of mathematics that deals with the analysis of random events. It provides a mathematical foundation to quantify and understand the likelihood of different outcomes.
In our exercise, we deal with several basic concepts of probability theory:
  • Probability of an event: This measures how likely an event is to occur. For example, the probability of choosing either box at random is \(\frac{1}{2}\).
  • Conditional Probability: This measures the probability of an event occurring given that another event has already occurred. For instance, the probability of picking a red ball from the second box given that you chose the second box is \(\frac{4}{9}\).
Essential formulas used in this exercise include:
  • Probability of picking a red ball from the first box (\(P(R|A)\)) and the second box (\(P(R|B)\)).
  • Total probability of drawing a red ball (\(P(R)\)), calculated by:
    \[P(R) = P(R|A)P(A) + P(R|B)P(B)\]
This structured approach helps simplify complex problems and apply logical methods to solve them.
Random Selection
Random Selection is a process where each item in a set has an equal chance of being chosen. This concept is central to many problems in probability theory, including our exercise.
In the context of our problem, randomness appears in two stages:
  • Choosing one of the two boxes (first or second) where the probability of each box being chosen is \(\frac{1}{2}\).
  • Picking a ball from the chosen box, where each ball has an equal chance of being selected.
This randomness ensures that the problem is fair and unbiased, allowing us to apply probability theory accurately.
To make informed decisions, it's crucial to understand the role of randomness. For the exercise, knowing that each box has the same chance of being chosen simplifies parts of the calculation. Random selection helps break down seemingly complicated problems into understandable steps, paving the way for applying conditional probability and Bayes' Theorem.

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Most popular questions from this chapter

Suppose it is known that \(1 \%\) of the population have a certain kind of cancer. It is also known that a test for this kind of cancer is positive in \(99 \%\) of the people who have it but is also positive in \(2 \%\) of the people who do not have it. What is the probability that a person who tests positive has cancer of this type?

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(a) Three typed letters and their envelopes are piled on a desk. If someone puts the letters into the envelopes at random (one letter in each), what is the probability that each letter gets into its own envelope? Call the envelopes \(A, B, C,\) and the corresponding letters \(a, b, c,\) and set up the sample space. Note that " \(a\) in \(C\) \(b\) in \(B, c\) in \(A "\) is one point in the sample space. (b) What is the probability that at least one letter gets into its own envelope? Hint: What is the probability that no letter gets into its own envelope? (c) Let \(A\) mean that \(a\) got into envelope \(A\), and so on. Find the probability \(P(A)\) that \(a\) got into \(A\). Find \(P(B)\) and \(P(C)\). Find the probability \(P(A+B)\) that either \(a\) or \(b\) or both got into their correct envelopes, and the probability \(P(A B)\) that both got into their correct envelopes. Verify equation (3.6)

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A so-called 7 -way lamp has three 60 -watt bulbs which may be turned on one or two or all three at a time, and a large bulb which may be turned to 100 watts, 200 watts or 300 watts. How many different light intensities can the lamp be set to give if the completely off position is not included? (The answer is not 7 .)

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