Use a series you know to show that \(\sum_{n=0}^{\infty} \frac{(1+i \pi)^{n}}{n !}=-e\).

Short Answer

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\(\sum_{n=0}^{fty} \frac{(1+i \pi)^{n}}{n!}=-e\).

Step by step solution

01

- Identify the Series

Recognize that the given sum \(\sum_{n=0}^{fty} \frac{(1+i \pi)^{n}}{n!}\) represents an exponential series. In general, the exponential series is given by \(e^{x} = \sum_{n=0}^{fty} \frac{x^{n}}{n!}\).
02

- Compare with the Exponential Series

Understand that \(\sum_{n=0}^{fty} \frac{(1+i \pi)^{n}}{n!}\) matches the form of the exponential series \(e^{x}\). Here, \(x = 1 + i \pi\).
03

- Apply the Exponential Series Formula

Using the exponential series formula, substitute \(x = 1 + i \pi\) into the formula to obtain \(e^{1 + i \pi}\).
04

- Simplify the Exponential Expression

Recall Euler's formula, which states \(e^{ix} = \cos(x) + i \sin(x)\). Therefore, \(e^{i \pi} = -1\). Substituting this into the expression, we get \(e^{1 + i \pi} = e e^{i \pi} = e (-1) = -e\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Euler's Formula
Euler's formula is a stunning result in mathematics, revealing a deep connection between complex exponentials and trigonometric functions. Euler's formula states that for any real number x, \br


Euler's formula is often used to solve problems involving complex numbers and trigonometry, making it a vital tool in various fields such as electrical engineering and physics. In the context of the given exercise, Euler's formula helps us simplify the complex exponential expression. For example, in Step 4 of the solution, we use the fact that \(e^{i \pi} = \cos(\pi) + i \sin(\pi)\). Since \(\cos(\pi) = -1\) and \(\sin(\pi) = 0\), we get \(e^{i \pi} = -1\). This result is crucial for simplifying and solving the given series. Understanding Euler's formula allows students to handle a broader range of problems involving complex numbers and exponential functions.
Complex Numbers
Complex numbers might seem daunting, but let's simplify the concept. A complex number is of the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit, satisfying \(i^2 = -1\). This makes complex numbers an extension of the real numbers. To grasp them better:

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Most popular questions from this chapter

Evaluate each of the following in \(x+i y\) form, and compare with a computer solution. $$i^{\ln i}$$

Express the following complex numbers in the \(x+i y\) form. Try to visualize each complex number, using sketches as in the examples if necessary. The first twelve problems you should be able to do in your head (and maybe some of the others- -try it!) Doing a problem quickly in your head saves time over using a computer. Remember that the point in doing problems like this is to gain skill in manipulating complex expressions, so a good study method is to do the problems by hand and use a computer to check your answers. $$2 e^{-i \pi / 2}$$

Prove that the conjugate of the quotient of two complex numbers is the quotient of the conjugates. Also prove the corresponding statements for difference and product. Hint: It is easier to prove the statements about product and quotient using the polar coordinate \(r e^{i \theta}\) form; for the difference, it is easier to use the rectangular form \(x+i y\).

Express the following complex numbers in the \(x+i y\) form. Try to visualize each complex number, using sketches as in the examples if necessary. The first twelve problems you should be able to do in your head (and maybe some of the others- -try it!) Doing a problem quickly in your head saves time over using a computer. Remember that the point in doing problems like this is to gain skill in manipulating complex expressions, so a good study method is to do the problems by hand and use a computer to check your answers. $$e^{i \pi}+e^{-i \pi}$$

Find one or more values of each of the following complex expressions and compare with a computer solution. $$\left(\frac{1+i}{1-i}\right)^{2718}$$

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