Find the equations of the following conics and quadric surfaces relative to principal axes. $$5 x^{2}+3 y^{2}+2 z^{2}+4 x z=14$$

Short Answer

Expert verified
The principal axes coordinates for the given ellipse equation are defined by transforming the original coordinates using the eigenvectors of the coefficient matrix.

Step by step solution

01

- Identify the general form of the quadric surface equation

The given equation is: \[ 5x^{2} + 3y^{2} + 2z^{2} + 4xz = 14 \]Recognize that this is a general second-degree polynomial for quadric surfaces.
02

- Rewrite the equation in matrix form

We can write the quadratic form as: \[ \begin{pmatrix} x & y & z \ \textbf{} \textbf{} \textbf{} \textbf{}\textbf{}\textbf{} \end{pmatrix} \begin{pmatrix} 5 & 0 & 2 \ 0 & 3 & 0 \ 2 & 0 & 2 \ \textbf{} \textbf{} \end{pmatrix} \begin{pmatrix} x \ y \ z \ \textbf{} \textbf{} \textbf{} \end{pmatrix} = 14 \]
03

- Determine the coefficient matrix

The coefficient matrix (A) from our quadratic terms, including off-diagonal terms, is:\[ A = \begin{pmatrix} 5 & 0 & 2 \ 0 & 3 & 0 \ 2 & 0 & 2 \ \textbf{} \end{pmatrix} \]
04

- Find the eigenvalues and eigenvectors

Solve for the eigenvalues and eigenvectors: Compute the characteristic polynomial from \( \text{det}(A - \lambda I) \). Solve for \( \lambda \) by finding the roots of the determinant.
05

- Diagonalization of the coefficient matrix

Using the eigenvectors, form the diagonal matrix \( D \) and the transformation matrix \( P \). \[ D = P^{-1}AP \]
06

- Write the transformed equation

Rewrite the original equation using the principal axes: \[ \lambda_{1} x'^{2} + \lambda_{2} y'^{2} + \lambda_{3} z'^{2} = 14 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eigenvalues and Eigenvectors
In this problem, finding the eigenvalues and eigenvectors of the coefficient matrix is crucial to understanding the quadric surface. An eigenvalue is a scalar that changes the magnitude but not the direction of an eigenvector when the matrix transforms that eigenvector.
To find the eigenvalues, solve the characteristic polynomial equation \(\text{det}(A - \text{{\textbackslash}}lambda I) = 0\) where \(A\) is the coefficient matrix and \(\text{{\textbackslash}}lambda\) represents the eigenvalues.
Next, compute the eigenvectors, which are the non-zero vectors \(v\) that satisfy \(Av = \text{{\textbackslash}}lambda v\). These vectors provide the directions in which the quadratic form can be simplified. This simplification is indispensable for understanding the geometric properties and orientation of the quadric surface.
The eigenvalues give you insights about the stretching or compressing of the surface along specific directions.
Eigenvectors, on the other hand, define the new coordinate axes for the principal axes transformation. This makes the quadric surface equation much easier to analyze.
Matrix Diagonalization
Matrix diagonalization is key to converting a complex quadratic form into a simpler one. Once you have the eigenvalues and eigenvectors, you can diagonalize the coefficient matrix. This process involves forming a diagonal matrix \(D\), which contains the eigenvalues on its diagonal entries, and a transformation matrix \(P\), which is formed from the eigenvectors.
The relationship between these matrices is given by \(D = P^{ -1}AP\). Transforming the original coefficient matrix \(A\) into a diagonal matrix \(D\) simplifies the quadratic form.
In the diagonal form, the quadratic surface equation can be written using the principal axes. Here, \(P^{ -1}\) represents the inverse of the transformation matrix. Matrix diagonalization is extremely helpful in simplifying the equations of quadric surfaces, allowing us to express them relative to their principal axes with ease.
Principal Axes Transformation
Principal axes transformation is the step where we use the results from eigenvalues and matrix diagonalization to rewrite the equation of a quadric surface in its simplest form. This transformation aligns the coordinate system with the principal axes of the surface, which are the directions indicated by the eigenvectors of the coefficient matrix.
When the quadratic equation is rewritten using the principal axes, its form becomes significantly simpler. In this case, you align the system of coordinates so that the matrix \(A\) is diagonal, which means there are no cross-product terms like \(xz\).
The transformed equation takes the form: \( \text{{\textbackslash}}lambda_{1} x'^{2} + \text{{\textbackslash}}lambda_{2} y'^{2} + \text{{\textbackslash}}lambda_{3} z'^{2} = 14 \) where \( \text{{\textbackslash}}lambda_{1}, \text{{\textbackslash}}lambda_{2}, \text{{\textbackslash}}lambda_{3} \) are the eigenvalues, and \( x', y', z' \) are the new coordinates along the principal axes.
This makes it far more straightforward to interpret the geometry of the surface, identify its type (ellipsoid, hyperboloid, etc.) and analyze its properties.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find a condition for four points in space to lie in a plane. Your answer should be in the form a determinant which must be equal to zero. Hint: The equation of a plane is of the form \(a x+b y+c z=d,\) where \(a, b, c, d\) are constants. The four points \(\left(x_{1}, y_{1}, z_{1}\right),\left(x_{2}, y_{2}, z_{2}\right),\) etc., are all to satisfy this equation. When can you find \(a\), \(b, c, d\) not all zero?

Let each of the following matrices M describe a deformation of the \((x, y)\) plane. For each given M find: the cigenvalues and eigenvectors of the transformation, the matrix \(\mathrm{C}\) which diagonalizes \(M\) and specifies the rotation to new axes \(\left(x^{\prime}, y^{\prime}\right)\) along the eigenvectors, and the matrix \(D\) which gives the deformation relative to the new axes. Describe the deformation relative to the new axes. $$\left(\begin{array}{ll} 5 & 2 \\ 2 & 2 \end{array}\right)$$

Verify that each of the following matrices is Hermitian. Find its eigenvalues and eigenvectors, write a unitary matrix U which diagonalizes \(\mathrm{H}\) by a similarity transformation, and show that \(U^{-1} H U\) is the diagonal matrix of eigenvalues. $$\left(\begin{array}{cc} 2 & i \\ -i & 2 \end{array}\right)$$

Find the eigenvalues and eigenvectors of the matrices in the following problems. $$\left(\begin{array}{ll} 4 & 2 \\ 2 & 1 \end{array}\right)$$

Show that the matrices $$\mathrm{I}=\left(\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right), \quad \mathrm{A}=\left(\begin{array}{cc} 0 & 1 \\ 1 & 0 \end{array}\right), \quad \mathrm{B}=\left(\begin{array}{rr} 0 & -1 \\ -1 & 0 \end{array}\right), \quad \mathrm{C}=\left(\begin{array}{rr} -1 & 0 \\ 0 & -1 \end{array}\right)$$ under matrix multiplication, form a group. Write the group multiplication table to see that this group (called the 4 's group) is not isomorphic to the cyclic group of order 4 in Problem 1. Show that the 4's group is Abelian but not cyclic.

See all solutions

Recommended explanations on Combined Science Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free