Show, by multiplying the matrices, that the following equation represents an ellipse. $$\left(\begin{array}{ll}x & y\end{array}\right)\left(\begin{array}{rr}5 & -7 \\\7 & 3 \end{array}\right)\left(\begin{array}{l}x \\\y\end{array}\right)=30.$$

Short Answer

Expert verified
The equation \(\frac{x^2}{6} + \frac{y^2}{10} = 1\) confirms it represents an ellipse.

Step by step solution

01

- Write Out the Matrices

Given the equation \[\left(\begin{array}{ll}x & y\end{array}\right)\left(\begin{array}{rr}5 & -7 \7 & 3 \end{array}\right)\left(\begin{array}{l}x \y\end{array}\right)=30\] Write out the matrices involved so that they are clear.
02

- Perform the Matrix Multiplication

First, multiply the two matrices on the right-hand side: \[ \left(\begin{array}{rr}5 & -7\7 & 3\end{array}\right) \left(\begin{array}{l}x \ y\end{array}\right) = \left(\begin{array}{c}5x - 7y\7x + 3y\end{array}\right) \] Then multiply the result by \( \left(\begin{array}{ll}x & y\end{array}\right)\): \[ \left(\begin{array}{ll}x & y\end{array}\right) \left(\begin{array}{c}5x - 7y\7x + 3y\end{array}\right) \]
03

- Final Matrix Multiplication

Now perform the final multiplication: \[(x)(5x - 7y) + (y)(7x + 3y)\] Distribute the terms: \[ 5x^2 - 7xy + 7xy + 3y^2 = 5x^2 + 3y^2 \]
04

- Set the Equation Equal to 30

Now set the result equal to 30: \[5x^2 + 3y^2 = 30\] This is the standard form of an ellipse equation: \[\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\]
05

- Verify it Matches the Ellipse Equation

Confirm that the equation matches the form of an ellipse by adjusting it: \[ \frac{5x^2}{30} + \frac{3y^2}{30} = 1\] \[ \frac{x^2}{6} + \frac{y^2}{10} = 1\] This confirms that the given matrix equation represents an ellipse.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Multiplication
Matrix multiplication is a fundamental algebraic operation used extensively in various mathematical disciplines. To multiply two matrices, align and pair their rows and columns. In the problem, we began by identifying the matrices involved in the equation: \( \begin{array}{ll}x & y\right)\) and \( \begin{array}{rr}5 & -7\7 & 3\right)\).

The process entails multiplying each element of the row by the corresponding element in the column and summing these products. When we multiplied these matrices, the intermediate result was: \( \begin{array}{c}5x - 7y\7x + 3y\right)\). Finally, the resulting vector was multiplied by \( \begin{array}{ll}x & y\right)\), yielding: \( (x)(5x - 7y) + (y)(7x + 3y) = 5x^2 + 3y^2\), which we set equal to 30. This method is effective for various applications, including transforming coordinate systems and solving systems of equations.
Ellipse Standard Form
An ellipse is a geometric shape characterized by its oval form and symmetric properties. The equation for an ellipse in standard form is given by: \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\).

In our problem, we derived the expression \( 5x^2 + 3y^2 = 30\) from the matrix multiplication. To convert this into the standard form of an ellipse, we divided both sides of the equation by 30, resulting in: \( \frac{5x^2}{30} + \frac{3y^2}{30} = 1\). This simplifies to: \( \frac{x^2}{6} + \frac{y^2}{10} = 1\), which is the equation of an ellipse.

Here, \( a^2 = 6\) and \( b^2 = 10\), making \( a = \frac{\text{3}}{\text{sqrt(2)}}\) and \( b = \frac{\text{sqrt(2)}}{\text{5}}\). The ellipse's axes lengths are determined by these values. Understanding how to manipulate and transform such equations is crucial for analyzing elliptical shapes in coordinate geometry.
Algebraic Proof
Algebraic proof involves demonstrating the validity of a mathematical statement using algebraic principles and logical reasoning. In this problem, our goal was to prove that the given matrix equation represents an ellipse.

We started by performing matrix multiplication in steps. First, we computed the product of the 2x2 and 2x1 matrices: \( \begin{array}{rr}5 & -7\7 & 3\right)\) and \( \begin{array}{l}x\y\right)\), resulting in \( \begin{array}{c}5x - 7y\7x + 3y\right)\). Second, we multiplied this result by \( \begin{array}{ll}x & y\ \right)\) to obtain the scalar expression \( 5x^2 + 3y^2\).

Upon establishing \( 5x^2 + 3y^2 = 30\), we compared this with the standard ellipse form, \( \frac{5x^2}{30} + \frac{3y^2}{30} = 1\), to confirm the ellipse representation. Such algebraic proofs are important for verifying mathematical concepts, ensuring correctness, and enhancing understanding of foundational principles in mathematics.

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Most popular questions from this chapter

Show that if \(D\) is a diagonal matrix, then \(D^{n}\) is the diagonal matrix with elements equal to the \(n^{\text {th }}\) power of the elements of \(\mathrm{D}\). Also show that if \(\mathrm{D}=\mathrm{C}^{-1} \mathrm{MC}\), then \(\mathrm{D}^{n}=\mathrm{C}^{-1} \mathrm{M}^{n} \mathrm{C},\) so \(\mathrm{M}^{n}=\mathrm{CD}^{n} \mathrm{C}^{-1} .\) Hint: For \(n=2,\left(\mathrm{C}^{-1} \mathrm{MC}\right)^{2}=\mathrm{C}^{-1} \mathrm{MCC}^{-1} \mathrm{MC}\) what is \(\mathrm{CC}^{-1} ?\)

Find the eigenvalues and eigenvectors of the following matrices. Do some problems by hand to be sure you understand what the process means. Then check your results by computer. $$\left(\begin{array}{rrr} -3 & 2 & 2 \\ 2 & 1 & 3 \\ 2 & 3 & 1 \end{array}\right)$$

Find the rank of each of the following matrices. $$\left(\begin{array}{lll} 1 & 1 & 2 \\ 2 & 4 & 6 \\ 3 & 2 & 5 \end{array}\right)$$

Show that each of the following matrices is orthogonal and find the rotation and/or reflection it produces as an operator acting on vectors. If a rotation, find the axis and angle; if a reflection, find the reflecting plane and the rotation, if any, about the normal to that plane. $$\frac{1}{11}\left(\begin{array}{rrr} 2 & 6 & 9 \\ 6 & 7 & -6 \\ 9 & -6 & 2 \end{array}\right)$$

Let each of the following matrices represent an active transformation of vectors in the (x, \(y\) ) plane (axes fixed, vectors rotated or reflected). As in Example \(3,\) show that each matrix is orthogonal, find its determinant, and find the rotation angle, or find the line of reflection. $$\left(\begin{array}{rr}0 & -1 \\\\-1 & 0\end{array}\right)$$.

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