The purpose in doing the following simple problems is to become familiar with the formulas we have discussed. So a good study method is to do them by hand and then check your results by computer. Compute the divergence and the curl of each of the following vector fields. $$\mathbf{r}=x \mathbf{i}+y \mathbf{j}$$

Short Answer

Expert verified
Divergence: 2, Curl: 0.

Step by step solution

01

Identify the Vector Field

Given the vector field \(\textbf{r} = x \textbf{i} + y \textbf{j}\), identify the components. Here, \(F_1 = x\) and \(F_2 = y\).
02

Compute the Divergence

The divergence of a vector field \(\textbf{F} = F_1 \textbf{i} + F_2 \textbf{j}\) is given by \( abla \bullet \textbf{F} = \frac{\forall F_1}{\forall x} + \frac{\forall F_2}{\forall y} \). Calculate each partial derivative: \(\frac{\forall F_1}{\forall x} = \frac{\forall x}{\forall x} = 1\) and \(\frac{\forall F_2}{\forall y} = \frac{\forall y}{\forall y} = 1\). Hence, \( abla \bullet \textbf{r} = 1 + 1 = 2 \).
03

Compute the Curl

In 2D, the curl of a vector field \( \textbf{F} = F_1 \textbf{i} + F_2 \textbf{j} \) is given by \( abla \times \textbf{F} = \frac{\forall F_2}{\forall x} - \frac{\forall F_1}{\forall y} \). Compute each partial derivative: \(\frac{\forall F_2}{\forall x} = \frac{\forall y}{\forall x} = 0\) and \(\frac{\forall F_1}{\forall y} = \frac{\forall x}{\forall y} = 0\). Therefore, \( abla \times \textbf{r} = 0 - 0 = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

curl
Simply put, the curl of a vector field measures the rotation or spiraling tendency of the field around a point. In a 2D vector field, the curl will be a scalar value. For a vector field \(\textbf{F} = F_1 \mathbf{i} + F_2 \mathbf{j}\), the formula for the curl is \(abla \times \textbf{F} = \frac{\partial F_2}{\partial x} - \frac{\partial F_1}{\partial y}\). Here, we need to compute the partial derivatives: \(\frac{\partial F_2}{\partial x}\) and \(\frac{\partial F_1}{\partial y}\). For the vector field given, these partial derivatives are \(\frac{\partial y}{\partial x} = 0\) and \(\frac{\partial x}{\partial y} = 0\). As a result, the curl of this particular vector field is 0. If the curl is zero, the field has no rotation.
vector field
A vector field is an assignment of a vector to each point in a subset of space. Think of it as a function that associates a vector with every point in space. For example, in a 2D plane, a vector field can be visualized as arrows pointing in different directions and having different lengths, depending on their position. The given vector field is \(\textbf{r} = x \mathbf{i} + y \mathbf{j}\). This means at any point \((x, y)\), the vector has its components as the coordinates themselves: \(x\textbf{i}\textbf{j}y\textbf{j}\). Such a vector field might represent things like the flow of fluid in a plane or the influence of some force at every point in space. Understanding vector fields is crucial as they provide a comprehensive way to describe physical phenomena such as velocity fields in fluid dynamics, electromagnetic fields, and gravitational fields among others.

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Most popular questions from this chapter

Prove that the triple scalar product of \((\mathbf{A} \times \mathbf{B}),(\mathbf{B} \times \mathbf{C}),\) and \((\mathbf{C} \times \mathbf{A}),\) is equal to the square of the triple scalar product of \(\mathbf{A}, \mathbf{B},\) and \(\mathbf{C} .\) Hint: First let \((\mathbf{B} \times \mathbf{C})=\mathbf{D},\) and evaluate \((\mathbf{A} \times \mathbf{B}) \times \mathbf{D} .\) [See Am. J. Phys. 66, 739 (1998).]

Given \(\mathbf{V}=x^{2} \mathbf{i}+y^{2} \mathbf{j}+z^{2} \mathbf{k},\) integrate \(\mathbf{V} \cdot \mathbf{n} d \sigma\) over the whole surface of the cube of side 1 with four of its vertices at \((0,0,0),(0,0,1),(0,1,0),(1,0,0) .\) Evaluate the same integral by means of the divergence theorem.

The position of a particle at time \(t\) is given by \(\mathbf{r}=\mathbf{i} \cos t+\mathbf{j} \sin t+\mathbf{k} t .\) Show that both the speed and the magnitude of the acceleration are constant. Describe the motion.

The force on a charge \(q\) moving with velocity \(\mathbf{v}=d \mathbf{r} / d t\) in a magnetic field \(\mathbf{B}\) is \(\mathbf{F}=q(\mathbf{v} \times \mathbf{B}) .\) We can write \(\mathbf{B}\) as \(\mathbf{B}=\boldsymbol{\nabla} \times \mathbf{A}\) where \(\mathbf{A}\) (called the vector potential) is a vector function of \(x, y, z, t .\) If the position vector \(\mathbf{r}=\mathbf{i} x+\mathbf{j} y+\mathbf{k} z\) of the charge \(q\) is a function of time \(t,\) show that $$\frac{d \mathbf{A}}{d t}=\frac{\partial \mathbf{A}}{\partial t}+\mathbf{v} \cdot \nabla \mathbf{A}$$ Thus show that $$\mathbf{F}=q \mathbf{v} \times(\mathbf{\nabla} \times \mathbf{A})=q\left[\nabla(\mathbf{v} \cdot \mathbf{A})-\frac{d \mathbf{A}}{d t}+\frac{\partial \mathbf{A}}{\partial t}\right]$$

Evaluate each integral in the simplest way possible. \(\iint(\operatorname{curl} \mathbf{V}) \cdot \mathbf{n} d \sigma\) over the entire surface of the cube in the first octant with three faces in the three coordinate planes and the other three faces intersecting at (2,2,2) where $$\mathbf{V}=(2-y) \mathbf{i}+x z \mathbf{j}+x y z \mathbf{k}$$

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