Find the inverse of:.20mod79,3mod62,21mod91,5mod23

Short Answer

Expert verified

Inverse of the given numbers is obtained.

Step by step solution

01

Inverse of 20 mod 79

GCD(20,79)79=(20×3,19)20=(19×1,1)GCD(20,79)=1soinverseof20mod79So,Bybackwardsubstitution,1=20-1×19=20-1×(79-3×20)=20-79+3×20=4×20-1×79.So,20-1=4mod79.

02

Inverse of 3 mod 62

GCD(3,62)62=(3×30,2)3=(2×1,1)GCD(3,62)is1so,inverseof3mod62is1=3-2=3-(62-20×3)=3-62+20×3=21×3-62×1So,3-1=21mod62.

03

Inverse of 21 mod 91

GCD(21,91)91=21×4,721=7×3,0So,HereGCD(21,91)is0soinverseisnotpossibleasperEuclidTheorem

04

Inverse of 5 mod 23

GCD(5,23)23=(5×4,3)5=(3×1,2)3=(2×1,1)GCD(5,23)isequalto1soinverseof5mod231=3-2=3-(5-3)=3×2-5×1=(23-4×5)×2-5×1=23×2-9×5So,5-1=-9=14mod23.

Hence, inverse of given numbers is obtained.

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