Show that if xis a nontrivial square root of 1 modulo N , that is if x21modNbut x±1modN, thenN must be composite. (For instance,421mod15but4±1mod15; thus 4 is a nontrivial square root of 1 modulo 15.)

Short Answer

Expert verified

It can be proved by the proof by contradiction method.

Step by step solution

01

Explain composite numbers

The multiple of two small positive integers that has atleast one divisor other than one.

02

Prove the given problem

By proof by contradiction method, Consider Ifx21modp,x±1modp and is a prime number. Then,

(xmodp)2-10modp(xmodp+1)(xmodp-1)0modp

Since,x±1modp , it is known that1xmodp-1<xmodp+1<p, ,and P is a prime number. Knowing thatxmodp±1 is relatively prime to p . Then by(xmodp+1)(xmodp-1)0modp, according to the division theorems,

xmodp±10modp, This is a contradiction.

So, p is a composite.

Therefore, it has been proved.

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Most popular questions from this chapter

Consider the problem of computing x y for given integers x and y: we want the whole answer, not modulo a third integer. We know two algorithms for doing this: the iterative algorithm which performs y − 1 multiplications by x; and the recursive algorithm based on the binary expansion of y. Compare the time requirements of these two algorithms, assuming that the time to multiply an n-bit number by an m-bit number is O(mn).

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ha1·ha1,a2(x1,x2)=a1x1+a2x2modm

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Quadratic residues. Fix a positive integer N. We say that a is a quadratic residue modulo N ifthere exists a such that ax2modN.
(a) Let N be an odd prime and be a non-zero quadratic residue modulo N. Show that there are exactly two values in{0,1,....,N-1} satisfying x2amodN.
(b) Show that if N is an odd prime, there are exactly(N+1)2 quadratic residues in {0,1,...,N-1}.
(c) Give an example of positive integers a and N such thatx2amodNhas more than two solutions in {0,1,...,N-1}.

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