You are given an array of nelements, and you notice that some of the elements are duplicates; that is, they appear more than once in the array. Show how to remove all duplicates from the array in time O(nlogn) .

Short Answer

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All duplicates are removed from the array in time: O(nlogn)

Step by step solution

01

Method-I

We may use pre-processing to eliminate duplicates by sorting the array. Its arrays sort consumes Onlogn time, and then we can verify if the last value is like the present value inside one pass; if it is, we don't display that number; otherwise, we do. We'll be able to get rid of the duplicates this way.

So the total amount of time is nLogn+1=OnLogn

02

Method-II

We need to perform nested loops if we haven't done the pre-processing yet. We execute one loop over the whole array (assuming index i and for each index i we check to see if the identical element is in the remaining set; if so, we do not print the element; otherwise, we do. Without pre-processing, the complexity will be ON2.

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