Chapter 1: Problem 17
Using the Properties of Order in Section \(1.4 .2,\) show that \\[ 5 n^{5}+4 n^{4}+6 n^{3}+2 n^{2}+n+7 \in \Theta\left(n^{5}\right) \\]
Chapter 1: Problem 17
Using the Properties of Order in Section \(1.4 .2,\) show that \\[ 5 n^{5}+4 n^{4}+6 n^{3}+2 n^{2}+n+7 \in \Theta\left(n^{5}\right) \\]
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Get started for freeWrite a linear-time algorithm that sorts \(n\) distinct integers ranging from 1 to 500 , inclusive. (Hint: Use a 500 -element array.)
Algorithm 1.7 (nth Fibonacci Term, Iterative) is clearly linear in \(n,\) but is it a linear-time algorithm? In Section 1.3 .1 we defined the input size as the size of the input. In the case of the \(nth\) Fibonacci term, \(n\) is the input, and the number of bits it takes to encode \(n\) could be used as the input size. Using this measure the size of 64 is \(\lg 64=6,\) and the size of 1024 is \(\lg 1024=\) 10\. Show that Algorithm 1.7 is exponential-time in terms of its input size. Show further that any algorithm for computing the \(nth\) Fibonacci term must be an exponential-time algorithm because the size of the output is exponential in the input size. See Section 9.2 for a related discussion of the input size.
Group the following functions by complexity category. $$n \ln n \quad(\lg n)^{2} \quad 5 n^{2}+7 n \quad n^\frac{5}{2} $$ $$n ! \quad 2^{n !} \quad 4^{n} \quad n^{n} \quad n^{n}+\ln n$$ $$5^{\text {Ig n}} \quad \lg (n !) \quad(\lg n) ! \quad \sqrt{n} \quad e^{n} \quad 8 n+12 \quad 10^{n}+n^{20}$$
What is the time complexity \(T(n)\) of the nested loops below? For simplicity, you may assume that \(n\) is a power of \(2 .\) That is, \(n=2^{k}\) for some positive integer \(k\) \(:\) \\[ \begin{array}{} \text { for }(i=1 ; i<=n, i++)\\} \\ \ \begin{array}{} j=n \\ \text { while }(j>=1)\\{ \end{array} \end{array} \\] < body of the while loop> \(\quad\) I/ Needs \(\Theta(1)\) \\[ j=\lfloor j / 2\rfloor \\] } }
Write an Insertion Sort algorithm that uses Binary Search to find the position where the next insertion should take place.
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