Consider the problem of adding the numbers in a list of \(n\) numbers, If it takes \(t_{d}(n-1)\) time for one person to add all \(n\) numbers, is it possible for \(m\) people to compute the sum in less than \(\left[t_{e}(n-1)\right] / m\) time? Justify your answer.

Short Answer

Expert verified
No, it is not possible for \(m\) people to compute the sum in less than \(\left[t_{e}(n-1)\right] / m\) time because addition is a sequential operation and cannot be effectively sped up by parallel processing.

Step by step solution

01

Understand the Concept of Sequential and Parallel Operations

Certain operations can be carried out in parallel, meaning they can be broken down into independent parts that can be executed simultaneously. Conversely, some operations are essentially sequential and cannot be speeded up by parallelizing. Addition of numbers is sequential in nature because you need the result of the previous operation (addition) to perform the next.
02

Analyze the Given Condition

According to the problem, it takes \(t_{d}(n-1)\) time for one person to add all \(n\) numbers. The question to consider is whether \(m\) people can compute the sum in less than \(\left[t_{e}(n-1)\right] / m\) time. For \(m\) people to add the \(n\) numbers more quickly than a single person, the addition task would need to be parallelizable. As established in Step 1, however, addition is inherently sequential in nature.
03

Formulate the Conclusion

Since addition is a sequential operation, distributing the work over \(m\) people does not speed up the process. Each new calculation must wait for the previous one to finish. Therefore, the time required to compute the sum would stay the same, even with multiple people working on it. Thus, it would not be possible for \(m\) people to compute the sum in less than \(\left[t_{e}(n-1)\right] / m\) time.

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