Write algorithms that perform the operations \(u \times 10^{m}\) \(u\) divide \(10^{n}\) \(u\) rem \(10 "\) where \(u\) represents a large integer, \(m\) is a nonnegative integer, divide returns the quotient in integer division, and rem returns the remainder. Analyze your algorithms, and show that these operations can be done in linear time.

Short Answer

Expert verified
To design the algorithms for these operations, use the properties of base 10 and the arithmetic operations. The multiplication and division operations can be done in linear time by shifting the digits of the number \(u\), while the remainder operation can also be done in linear time by returning the last digit of \(u\).

Step by step solution

01

Multiplication by powers of 10

The operation \ \(u \times 10^{m}\) is implemented by shifting the digits of 'u' to the left by 'm' places, effectively multiplying 'u' by \(10^m\). Since each shift operation is performed in constant time, the overall time complexity of this operation is O(m), which in the worst case is equal to O(n), where n is the number of digits in 'u'. Append 'm' zeroes to the end of 'u' to accomplish this.
02

Division by powers of 10

The operation \(\frac{u}{10^{n}}\) is implemented by shifting the digits of 'u' to the right by 'n' places, essentially dividing 'u' by \(10^n\). As before, each shift operation is performed in constant time, establishing the overall time complexity of this operation as O(n). To get the quotient, remove the last 'n' digits from 'u'.
03

Remainder Operation

The operation '\(u\) rem 10' involves finding the remainder when 'u' is divided by 10. In terms of digits, this is the last digit of 'u'. Retrieving the last digit of 'u' can be done in constant time, O(1), which for large 'u' can be approximated as linear time, O(n). Thus, the last digit of 'u' is the remainder when 'u' is divided by 10.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integer Operations
When dealing with algorithms that perform operations on integers, understanding how integer operations work is crucial for writing efficient code. Specifically, operations involving multiplication, division, and finding remainders of large integers by powers of 10 can be optimized.

For instance, the operation of multiplying an integer by a power of 10, as represented by the exercise through the expression \( u \times 10^{m} \), is streamlined by shifting digits. Imagine having the number 123 and multiplying it by 100 (which is \( 10^2 \)); the result, 12300, is achieved by appending two zeros. This is a very swift operation that avoids the complexities of traditional multiplication.

When it comes to division by a power of 10, \( \frac{u}{10^{n}} \), the concept is quite similar but in reverse. Removing 'n' digits from the end of the number yields the quotient. For example, dividing 12300 by 100 involves stripping away the last two zeros, effectively leaving us with 123.

In programming, these types of integer operations are far faster than standard arithmetic operations since they involve merely shifting digits, which can be done in constant time for each shift operation. This characteristic makes these operations highly efficient when dealing with large numbers.
Linear Time Algorithms
Understanding algorithmic complexity is vital for developing not only correct solutions but also efficient ones. Linear time algorithms, in particular, have complexities that grow linearly with the size of the input data. This means that if we double the input size, the time it takes to complete the operation will also roughly double.

The operations described in the original exercise are excellent examples of linear time algorithms. Whether you're multiplying by \( 10^m \), dividing by \( 10^n \), or finding the remainder with 10, each of these operations can be done in a number of steps proportional to the number of digits in the integer \( u \).

To clarify using the exercise as an example, multiplying by \( 10^m \) adds 'm' digits to 'u', and thus the algorithm's performance is directly tied to 'm'. The same goes for dividing by \( 10^n \), which involves examining or manipulating 'n' digits of 'u'. These straightforward operations guarantee linear time complexity, ensuring that no matter how large the integer 'u' gets, the time required to finish the operation scales sensibly alongside the size of 'u'.
Pseudo Code
Pseudo code is an incredibly valuable tool for communicating the logic of an algorithm without getting bogged down in the syntax of a programming language. It allows for the presentation of the 'big picture' of the algorithm's workflow, focusing on the logic rather than the implementation details.

Let's consider pseudo code for the multiplication part of the problem:
  • ALGORITHM MultiplyByPowerOfTen(u, m)
  • FOR i FROM 1 TO m
  • APPEND '0' TO THE END OF u
  • END FOR
  • RETURN u
This pseudo code encapsulates the process of multiplying an integer 'u' by \( 10^m \) by explicitly appending zeros 'm' times, which is an intuitive representation of the steps outlined in the exercise's solution.

Pseudo code is not just a tool for beginners; it is often used by seasoned developers to draft algorithms and communicate ideas clearly. Writing pseudo code first can save time and ensure that the logic of your solution is solid before diving into actual code, where the intricacies of a language might otherwise obstruct the clarity of the algorithmic design.

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Most popular questions from this chapter

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