Discuss the reflexive, symmetric, and transitive properties for asymptotic comparisons \((O, \Omega, \Theta, o)\)

Short Answer

Expert verified
Big-O, \(\Omega\), and \(\Theta\) follow the reflexive and transitive properties. \(\Theta\) also follows the symmetric property. Little-o does not follow the reflexive property but does follow the transitive.

Step by step solution

01

Understanding the properties

Before discussing whether these properties apply to the asymptotic notations or not, let's understand what these properties mean. Reflexive property means that for any set 'a', \(aRa\) holds true. Symmetric property means that for any set 'a' and 'b', if \(aRb\) holds true, then \(bRa\) should also be true. Transitive property means that if \(aRb\) and \(bRc\) are true, then \(aRc\) should be true.
02

Discussing the Reflexive Property

In terms of Big-O notation, for any function 'f', we can say \(f = O(f)\). Similarly \(\Omega\) and \(\Theta\) notations satisfy the reflexive property, as \(f = \Omega(f), f = \Theta(f)\). However, little-o notation does not satisfy, because for \(f = o(f)\) to be true, \(f\) should be strictly less than 'f', which clearly is not.
03

Discussing the Symmetric Property

In terms of Big-O notation, if \(f = O(g)\), then it doesn't necessarily mean that \(g = O(f)\). So, Big-O doesn't satisfy the symmetric property. Same goes for \(\Omega\) and little-o notation. However, for \(\Theta\) notation, if \(f = \Theta(g)\), then it means that \(g = \Theta(f)\). Hence, \(\Theta\) follows the symmetric property.
04

Discussing the Transitive Property

In terms of Big-O notation, if \(f = O(g)\) and \(g = O(h)\), then \(f = O(h)\). Therefore, Big-O follows the transitive property. Same goes for \(\Omega\) and \(\Theta\) notation and little-o notation. All follow the transitive property.

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