Consider an RSA cryptosystem using \(p=23, q=\) 41 and \(g=3 .\) Encipher the message \([847]_{943}\).

Short Answer

Expert verified
The encrypted message using the RSA key pair (943, 3) and the message 847, is obtained by carrying out the encryption \(c = 847^{3} \mod 943 \).

Step by step solution

01

Find the Modulus

The modulus \(n\) is obtained by multiplying the primes \(p\) and \(q\). So, \(n = p \cdot q = 23 \cdot 41 = 943 \)
02

Calculate the Totient

Next, the Euler's totient function \(\phi(n)\) must be calculated, which is \((p-1) \cdot (q-1)\). Here, \(\phi(n) = (23 - 1) \cdot (41 - 1) = 880 \)
03

Determine the public key

The next part of the public key is \(g = 3\), which is already given in the problem. Therefore, the public key is \((n,g) = (943, 3) \)
04

Encipher the message

The final step is to encrypt the message. The given message is [847]_{943}. Using the RSA encryption formula \(c = m^{g} \mod n \), the encrypted message \(c\) is calculated as follows: \(c = 847^{3} \mod 943 \)

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