Given the recurrence relation \\[\begin{array}{l} T(n)=7 T\left(\frac{n}{5}\right)+10 n \quad \text { for } n>1 \\\T(1)=1\end{array}\\] find \(T(625)\)

Short Answer

Expert verified
The solution to the recurrence relation \(T(625) = T(7)T\left(\frac{n}{5}\right) + 10 n\) given \(T(1) = 1\) is \(T(625) = 65151\).

Step by step solution

01

Start with the given \(n\)

We are asked to find \(T(625)\). To calculate this, we will first substitute \(n=625\) into the recurrence relation.
02

Apply Recurrence Relation

Substitute \(n=625\) into the recurrence relation to get \(T(625) = 7T(125) + 6250\). Now, we need to calculate \(T(125)\). Repeat the same process i.e., substitute \(n=125\) into the recurrence relation to get \(T(125) = 7T(25) + 1250\). Continue this iterative process until we reach \(T(1)\).
03

Final Calculation

Here we will repeatedly substitute \(n\) in the relation till we reach \(T(1)\): \(T(625) = 7T(125) + 6250 = 7[7T(25) + 1250] + 6250 = 49T(25) + 13750 = 49[7T(5) + 250] + 13750 = 343T(5) + 24350 = 343[7T(1) + 50] + 24350 = 2401T(1) + 41150 = 2401*1 + 41150 = 65151\).

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