Write the dynamic programming algorithm for the 0 -1 Knapsack problem.

Short Answer

Expert verified
Initialize a table with 'items+1' rows and 'knapsack capacity+1' columns, filling the first row and column with zeroes. Then fill the rest of the table for each item and each weight capacity, taking into consideration the weight of the current item. Finally, the maximum profit or optimal solution is stored at the last cell of the table, representing the full capacity and all items.

Step by step solution

01

Title - Initialize a table

First, create an array or table with rows equal to the number of items plus one, and columns equal to the weight of the knapsack plus one. Now, initialize the first row and first column of this array to zeroes. The row zero represents zero items and the column zero indicates zero capacity of knapsack. This signifies that if there are no items or the knapsack capacity is zero, then the maximum profit possible is zero.
02

Title - Populate the Remaining Table

For each item, start from one up to the total number of items. For each weight capacity, start from one up to the total knapsack capacity. If the weight of the current item is greater than the current weight capacity, then copy the maximum profit from the previous item into the current position. Else, take the maximum of either the value of the previous item or the sum of the value of the current item and the maximum profit from the remaining weight capacity (which is obtained from the previous row). Continue doing this until the last item and last weight capacity is reached.
03

Title - Retrieve the Optimal Solution

The optimal solution or the maximum profit that can be achieved is stored at the last row and the last column of the table. This is because this cell represents considering all items and the total weight capacity of the knapsack. Therefore, the value at this position will be our answer.

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